[英]how to use foreign key in Room persistence library
我正在 android 中使用房間持久性庫,如果有人可以幫助我使用外鍵,如何使用外鍵獲取數據,我將不勝感激。
只是為未來的讀者總結上述帖子:
Kotlin 中的外鍵語法是
@Entity(foreignKeys = arrayOf(ForeignKey(entity = ParentClass::class,
parentColumns = arrayOf("parentClassColumn"),
childColumns = arrayOf("childClassColumn"),
onDelete = ForeignKey.CASCADE)))
Java 中的外鍵語法是:
@Entity(foreignKeys = {@ForeignKey(entity = ParentClass.class,
parentColumns = "parentClassColumn",
childColumns = "childClassColumn",
onDelete = ForeignKey.CASCADE)
})
注意:foreignKeys 是一個數組,所以在 Java 中將 @ForeignKey 元素括在 { 和 } 中
您可以參考官方文檔了解更多信息。 https://developer.android.com/reference/androidx/room/ForeignKey
在這里,您如何在 Android Jetpack Room 中定義和訪問一對多(外鍵)關系。 這里的實體是Artist
和Album
,外鍵是Album.artist
@Entity
data class Artist(
@PrimaryKey
val id: String,
val name: String
)
@Entity(
foreignKeys = [ForeignKey(
entity = Artist::class,
parentColumns = arrayOf("id"),
childColumns = arrayOf("artist"),
onDelete = ForeignKey.CASCADE
)]
)
data class Album(
@PrimaryKey
val albumId: String,
val name: String,
@ColumnInfo(index = true)
val artist: String
)
然后嵌入對象( 閱讀官方 Android 文檔:定義對象之間的關系)
data class ArtistAndAlbums(
@Embedded
val artist: Artist,
@Relation(
parentColumn = "id",
entityColumn = "artist"
)
val albums: List<Album>
)
最后是DAO
@Dao
interface Library {
@Insert
suspend fun save(artist: Artist)
@Insert
suspend fun save(vararg album: Album)
@Transaction
@Query("SELECT * FROM artist")
suspend fun getAll(): List<ArtistAndAlbums>
@Transaction
@Query("SELECT * FROM artist WHERE id = :id")
suspend fun getByArtistId(id: String): ArtistAndAlbums
}
試試這個,(所有這些操作都發生在協程中)
// creating objects
val artist = Artist(id="hillsongunited", name="Hillsong United" )
val artist2 = Artist(id="planetshakers", name="Planet Shakers" )
val album1 = Album(albumId = "empires", name = "Empires", artist = artist.id)
val album2 = Album(albumId = "wonder", name = "Wonder", artist = artist.id)
val album3 = Album(albumId = "people", name = "People", artist = artist.id)
val album4 = Album(albumId = "rain", name = "Rain", artist = artist2.id)
val album5 = Album(albumId = "itschristmas", name = "Its Christmas", artist = artist2.id)
val album6 = Album(albumId = "overitall", name = "Over It All", artist = artist2.id)
// saving to database
SongDatabase.invoke(applicationContext).library().save(artist)
SongDatabase.invoke(applicationContext).library().save(artist2)
SongDatabase.invoke(applicationContext).library().save(album1, album2, album3, album4, album5, album6)
注銷所有藝術家
val all = SongDatabase.invoke(applicationContext).library().getAll()
Log.d("debug", "All Artists $all ")
D/debug: All Artists [ArtistAndAlbums(artist=Artist(id=hillsongunited, name=Hillsong United), albums=[Album(albumId=empires, name=Empires, artist=hillsongunited), Album(albumId=wonder, name=Wonder, artist=hillsongunited), Album(albumId=people, name=People, artist=hillsongunited)]), ArtistAndAlbums(artist=Artist(id=planetshakers, name=Planet Shakers), albums=[Album(albumId=rain, name=Rain, artist=planetshakers), Album(albumId=itschristmas, name=Its Christmas, artist=planetshakers), Album(albumId=overitall, name=Over It All, artist=planetshakers)])]
注銷特定藝術家的專輯,
val hillsongAlbums = SongDatabase.invoke(applicationContext).library().getByArtistId(artist.id)
Log.d("debug", "Albums by artist ID: $hillsongAlbums ")
D/debug: Albums by artist ID: ArtistAndAlbums(artist=Artist(id=hillsongunited, name=Hillsong United), albums=[Album(albumId=empires, name=Empires, artist=hillsongunited), Album(albumId=wonder, name=Wonder, artist=hillsongunited), Album(albumId=people, name=People, artist=hillsongunited)])
我使用了一個不錯的教程:
https://medium.com/@tonyowen/room-entity-annotations-379150e1ca82
它也提供有關以下信息: @embeded, @ignore,@ColumnInfo
當我們使用外鍵時,不要忘記使用onDelete = ForeignKey.CASCADE
這樣的方式,如果您刪除數據,它也會刪除依賴關系。 這樣,您就不會有錯誤的數據或永遠不會使用的數據
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