[英]MongoDB query subarray in sub array
我想從我的文檔中獲取unitHouse,這是sub array的sub array這是數據
{
"_id" : ObjectId("5a17d305c438324308bffb19"),
"floorRow" : [
{
"floorRowNo" : "F1",
"floorRowInfo" : "Best Floor Ever that i have ever seen",
"_id" : ObjectId("5a17d333c438324308bffb1a"),
"unitHouse" : [
]
},
{
"floorRowNo" : "F2",
"floorRowInfo" : "view",
"_id" : ObjectId("5a1bdfbb4d63841c3cb6fc89"),
"unitHouse" : [
{
"unitHouseNo" : "Unit001",
"unitHouseType" : "OFFICE",
"unitHouseStatus" : "SELL",
"_id" : ObjectId("5a1d212bed3a552f0421fd6b"),
},
{
"unitHouseNo" : "Unit002",
"unitHouseType" : "CAT003",
"unitHouseStatus" : "SELL",
"_id" : ObjectId("5a1e3691af12544ff05690e3"),
}
]
}
],
}
到目前為止,這是我一直在查詢的內容,我可以得到我想要的F2層,但是兩個單元都附帶了它。 我只想要id為5a1e3691af12544ff05690e3的unitHouse。
propertyDevModel.aggregate([
{
$match: {
_id: mongoose.Types.ObjectId("5a17d305c438324308bffb19"),
}
},
{
$project: {
floorRow: {
$filter: {
input: '$floorRow',
as: 'floorRow',
cond: {
$eq: ['$$floorRow._id', mongoose.Types.ObjectId("5a1bdfbb4d63841c3cb6fc89")],
}
}
}
}
},
])
我已經親自回答了這個問題,但是我會保留這個帖子給其他有同樣問題的人。
db.aggregate([
{
$match: {
_id: projectId,
'floorRow._id': floorRowId
}
},
{$unwind: '$floorRow'},
{
$match: {
'floorRow._id': floorRowId
}
},
{$unwind: '$floorRow.unitHouse'},
{
$match: {
'floorRow.unitHouse._id': unitId
}
},
{
$project:{
'floorRow.unitHouse': 1
}
}
])
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