[英]Python list to tuple
我有這個 :
(([75, 0], [100, 0], [100, 370]), ([75, 0], [100, 370], [75, 370]))
來自這個:
[(array([75, 0]), array([100, 0]), array([100, 370])), (array([75, 0]), array([100, 370]), array([ 75, 370]))]
我想擁有:
[(x1, y1, x2 , y2 ,x3 ,y3), (x1, y1, x2 , y2 ,x3 ,y3), ...]
要么
[(75, 0, 100, 0, 100, 370), (75, 0, 100, 0, 100, 370),.....]
謝謝您的幫助!
您可以使用itertools.chain
:
import itertools
s = (([75, 0], [100, 0], [100, 370]), ([75, 0], [100, 370], [75, 370]))
final_s = [list(itertools.chain.from_iterable(i)) for i in s]
輸出:
[[75, 0, 100, 0, 100, 370], [75, 0, 100, 370, 75, 370]]
或使用reduce
在Python2:
s = (([75, 0], [100, 0], [100, 370]), ([75, 0], [100, 370], [75, 370]))
new_s = [reduce(lambda x, y:list(x)+list(y), i) for i in s]
輸出:
[[75, 0, 100, 0, 100, 370], [75, 0, 100, 370, 75, 370]]
您可以使用列表理解:
>>> t = (([75, 0], [100, 0], [100, 370]), ([75, 0], [100, 370], [75, 370]))
>>> [tuple(sub for el in l for sub in el) for l in t]
[(75, 0, 100, 0, 100, 370), (75, 0, 100, 370, 75, 370)]
易於理解的版本:
original = (([75, 0], [100, 0], [100, 370]), ([75, 0], [100, 370], [75, 370]))
final = []
for each_tuple in original:
final_child_list = []
for each_list in each_tuple:
final_child_list.extend(each_list)
final.append(final_child_list)
你會得到:
>>> final
[[75, 0, 100, 0, 100, 370], [75, 0, 100, 370, 75, 370]]
# if you prefer the inside element to be tuples
>>> [tuple(x) for x in final]
[(75, 0, 100, 0, 100, 370), (75, 0, 100, 370, 75, 370)]
使用列表理解的版本可能更短,但可讀性較低。
從此示例開始:
from operator import add
from functools import reduce
reduce(add, (x for x in [[1, 2], [3, 4]]))
輸出:
[1、2、3、4]
現在,只需對元組中的每個元素執行此操作:
[tuple(reduce(add, x)) for x in data]
輸出:
[(75,0,100,0,100,370),(75,0,100,370,75,370)]
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