如何讀取一行中每個int的.txt文件並存儲到數組中？

Question

public class assignment2
{
    public static void main(String[] args) throws IOException 
    {
        // TODO Auto-generated method stub
        FileInputStream fstream = new FileInputStream("assignment2.txt");
        BufferedReader br = new BufferedReader(new InputStreamReader(fstream));

        String strLine;

        //Read File Line By Line
        while ((strLine = br.readLine()) != null) {
            // Print the content on the console
            System.out.println (strLine);
            String[] numbers = strLine.split(" ");
            System.out.print(numbers[1]);
        }
        //Close the input stream
        br.close();
    }
}

我希望代碼將String []數字打印為1 0 10

我得到這個結果00371010

請注意，輸入文件的格式如下：

1 0 10

2 0 9

3 3 5

4 7 4

5 10 6

6 10 7

Answer 1

只需替換您的行：

System.out.print(numbers[1]);

附：

for (int i = 0; i < numbers.length; i++)
    System.out.print(numbers[i] + " ");

System.out.println();

讓我知道它是如何工作的。

Answer 2

您需要通過添加另一個循環來修改代碼，如下所示：

public static void main(String[] args) throws IOException {
    // TODO Auto-generated method stub
    FileInputStream fstream = new FileInputStream("assignment2.txt");
    BufferedReader br = new BufferedReader(new InputStreamReader(fstream));
    String strLine;

    //Read File Line By Line
    while ((strLine = br.readLine()) != null){
        // Print the content on the console
        System.out.println (strLine);
        String[] numbers = strLine.split(" ");
        for (String num : numbers){
            System.out.print(num + " ");
        }
        System.out.println("\n");
    }
    //Close the input stream
    br.close();
}

因為，numbers [1]僅將索引1上的值打印出來。