如何將 std::regex_token_iterator 復制到 std::vector？

Question

下面的代碼無法將值從 regex_token_iterator 復制到 std::vector； Visual Studio 2015 報告帶有參數的“std::copy”可能不安全。

有誰知道如何修復它？

#include <vector>
#include <iostream>
#include <algorithm>
#include <iterator>
#include <regex>

int main()
{
    // String to split in words
    std::string line = "dir1\\dir2\\dir3\\dir4";

    // Split the string in words
    std::vector<std::string> to_vector;
    const std::regex ws_re("\\\\"); 
    std::copy(std::sregex_token_iterator(line.begin(), line.end(), ws_re, -1),
              std::sregex_token_iterator(),
              std::back_insert_iterator<std::vector<std::string>>(to_vector));

    // Display the words
    std::cout << "Words: ";
    std::copy(begin(to_vector), end(to_vector), std::ostream_iterator<std::string>(std::cout, "\n"));
}

Answer 1

這是我將 regex_token_iterator 提取的值存儲到向量的解決方案：

#include <vector>
#include <iostream>
#include <algorithm>
#include <iterator>
#include <regex>

int main()
{
    std::string s("dir1\\dir2\\dir3\\dir4");

    // Split the line in words
    const std::regex reg_exp("\\\\");
    const std::regex_token_iterator<std::string::iterator> end_tokens;
    std::regex_token_iterator<std::string::iterator> it(s.begin(), s.end(), reg_exp, -1);
    std::vector<std::string> to_vector;
    while (it != end_tokens)
    {
        to_vector.emplace_back(*it++);
    }

    // Display the content of the vector
    std::copy(begin(to_vector), 
              end(to_vector), 
              std::ostream_iterator<std::string>(std::cout, "\n"));

    return 0;
}

Answer 2

非常舊的代碼，但因為我也在尋找解決方案。 很簡單，第三個參數應該是 back_inserter 到 vector。

std::copy(std::sregex_token_iterator(line.begin(), line.end(), ws_re, -1),
          std::sregex_token_iterator(),
          std::back_inserter(to_vector));