[英]postgresql key contraint fault
我嘗試為postgresql創建代碼
CREATE TABLE kaart (
kaartid integer NOT NULL,
naam character varying,
saldo real,
kaarthouderid integer
);
CREATE TABLE kaart_product (
kaartkaartid integer,
productid2 integer
);
CREATE TABLE kaarthouder (
id integer NOT NULL,
naam character varying(255),
naw character varying(255),
geslacht "char"
);
CREATE TABLE product (
naam character varying,
id integer NOT NULL
);
ALTER TABLE ONLY kaart
ADD CONSTRAINT kaart_pkey PRIMARY KEY (kaartid);
ALTER TABLE ONLY kaarthouder
ADD CONSTRAINT kaarthouder_pkey PRIMARY KEY (id);
ALTER TABLE ONLY product
ADD CONSTRAINT product_pkey PRIMARY KEY (id);
ALTER TABLE ONLY kaart
ADD CONSTRAINT kaartco FOREIGN KEY (kaartid) REFERENCES kaarthouder(id) ON UPDATE CASCADE ON DELETE CASCADE;
ALTER TABLE ONLY kaart_product
ADD CONSTRAINT kaartkaartidco FOREIGN KEY (kaartkaartid) REFERENCES kaart(kaartid) ON UPDATE CASCADE ON DELETE CASCADE;
ALTER TABLE ONLY kaart_product
ADD CONSTRAINT productidco FOREIGN KEY (kaartkaartid) REFERENCES product(id) ON UPDATE CASCADE ON DELETE CASCADE;
INSERT INTO kaart VALUES (1, 'Sander',50.00 ,1);
INSERT INTO kaart_product VALUES (1,1);
INSERT INTO kaarthouder VALUES (1, 'Sander','test,testing','man');
INSERT INTO product VALUES ('studentenproduct',1);
但是,每當我嘗試運行它時,都會出現此錯誤:
23503:在表“ kaart”上插入或更新違反了外鍵約束“ kaartco”
但是我真的不知道為什么會發生這種情況,因為它與它下面的其他外鍵相同
有人可以幫我解決這個問題嗎?
您嘗試鏈接到尚不存在的產品和kaart。
移動:
INSERT INTO kaart_product VALUES (1,1);
下兩行:
INSERT INTO product VALUES ('studentenproduct',1);
那應該為您完成工作。 嘗試在Google上搜索forgein關鍵約束及其工作方式。
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