如何從PHP中的URL獲取圖像的大小？

Question

我一直試圖從網址中獲取圖像的大小，但它不起作用。 誰能幫我？

這是代碼：

$imagesize = getimagesize('https://www.dropbox.com/s/hbtmge2omlyqx2n/BrownBag.jpg?dl=0');
echo $imagesize;

Answer 1

你沒有在這個網址中獲取圖片https://www.dropbox.com/s/hbtmge2omlyqx2n/BrownBag.jpg?dl=0

您需要得到的是圖像地址 ，這是https://photos-5.dropbox.com/t/2/AADa4bq7fis50BvRTojhB5zvAJDLNwsLDb5dekkb4JfilQ/12/502094097/jpeg/32x32/3/1513760400/0/2/BrownBag.jpg/ EJrFv4kEGLgCIAIoAg / cwCCXcZopeYId4BrstNKJ6qGETjrin47oEgU6B50AE0？DL = 0＆大小= 1280×960＆size_mode = 3

碼

$imagesize = getimagesize('https://photos-5.dropbox.com/t/2/AADa4bq7fis50BvRTojhB5zvAJDLNwsLDb5dekkb4JfilQ/12/502094097/jpeg/32x32/3/1513760400/0/2/BrownBag.jpg/EJrFv4kEGLgCIAIoAg/cwCCXcZopeYId4BrstNKJ6qGETjrin47oEgU6B50AE0?dl=0&size=1280x960&size_mode=3');
print_r($imagesize);

結果

Array
(
    [0] => 1000
    [1] => 750
    [2] => 2
    [3] => width="1000" height="750"
    [bits] => 8
    [channels] => 3
    [mime] => image/jpeg
)

你也可以在上傳后參考這個Dropbox獲取文件的公共URL

只需更改：

https://www.dropbox.com/s/hbtmge2omlyqx2n/BrownBag.jpg?dl=0

至

https://dl.dropbox.com/s/hbtmge2omlyqx2n/BrownBag.jpg

只需用dl替換www並刪除?dl=0

Answer 2

您需要使用Dropbox的圖像路徑

$imagesize = getimagesize('https://photos-5.dropbox.com/t/2/AADa4bq7fis50BvRTojhB5zvAJDLNwsLDb5dekkb4JfilQ/12/502094097/jpeg/32x32/3/1513760400/0/2/BrownBag.jpg/EJrFv4kEGLgCIAIoAg/cwCCXcZopeYId4BrstNKJ6qGETjrin47oEgU6B50AE0?dl=0&size=1600x1200&size_mode=3');
echo $imagesize;