聚合物DOM重復內容取決於接收的數據

Question

我做了一個DOM重復，它可以接收多種類型的數據。
現在，我希望DOM重復僅顯示與該類型相關的項目。
有可能做到這一點，我將如何實現呢？
當item.Type為Zone時，我希望它顯示item.Name和item.ZoneID
當item.Type為Building時，我希望它顯示item.BuildingID，item.Address1和item.Address2

這是我的代碼：

 <template is="dom-repeat" items="[[data]]">
          <paper-card id="departmentspaperContainer2">
            <div class="card-content">
              <h3>Type: {{item.Type}}</h3>
              <hr/>
              <h4>Name:       {{item.Name}}</h4>
              <h4>BuildingID: {{item.BuildingID}}</h4>
              <h4>ZoneID:     {{item.ZoneID}}</h4>
              <h4>Address1:   {{item.Address1}}</h4>
              <h4>Address2:   {{item.Address2}}</h4>
            </div>
          </paper-card>
        </template>

Answer 1

與“ HakanC”的提議類似，但不同的是，您可以使用dom-if並綁定過濾器函數的響應：

這是一個工作的jsfiddle （在chrome中使用）

<dom-module id="os-test">
    <template>
        <template is="dom-repeat" items="{{data}}">
            <paper-card id="departmentspaperContainer2">
                <div class="cardContent" type="{{item.Type}}">
                  <h3>Type: [[item.Type]]</h3>
                  <hr/>
                  <template is='dom-if' if='{{showZone(item.Type)}}'>
                     <h4>Name: [[item.Name]]</h4>
                     <h4>ZoneID: [[item.ZoneID]]</h4>
                  </template>
                  <template is='dom-if' if='{{showBuilding(item.Type)}}'>
                     <h4>BuildingID:[[item.BuildingID]]</h4>
                     <h4>Address1: [[item.Address1]]</h4>
                     <h4>Address2: [[item.Address2]]</h4>
                  </template>
                </div>
            </paper-card>
        </template>
    </template>
</dom-module>
<script>
  class OsTestElement extends Polymer.Element {
    static get is() {
      return 'os-test';
    }

    static get properties() {
      return {
        data: {
          type: Array,
          value: () => {
            return [
                {
                Type:"Zone",
                Name:"valueName1",
                BuildingID:"valueBuildingID1",
                ZoneID:"valueZoneID1",
                Address1:"valueAddress11",
                Address2:"valueAddress21",
              },
              {
                Type:"Zone",
                Name:"valueName2",
                BuildingID:"valueBuildingID2",
                ZoneID:"valueZoneID2",
                Address1:"valueAddress12",
                Address2:"valueAddress22",
              },
              {
                Type:"Building",
                Name:"valueName3",
                BuildingID:"valueBuildingID3",
                ZoneID:"valueZoneID3",
                Address1:"valueAddress13",
                Address2:"valueAddress23",
              },
              {
                Type:"Building",
                Name:"valueName4",
                BuildingID:"valueBuildingID4",
                ZoneID:"valueZoneID4",
                Address1:"valueAddress14",
                Address2:"valueAddress24",
              }
            ]
          }
        }
      }
    }

    showZone(item) {
        return (item==="Zone");
    }

    showBuilding(item) {
        return (item==="Building");
    }
  }
  window.customElements.define(OsTestElement.is, OsTestElement);
</script>

Answer 2

您可以將dom-if用作dom-repeat休假。

<template is="dom-repeat" items="[[data]]">
          <paper-card id="departmentspaperContainer2">
            <div class="card-content">
              <h3>Type: {{item.Type}}</h3>
              <hr/>
              <h4>Name:       {{item.Name}}</h4>

              <template is='dom-if' if='{{_show(item.Type)}}'>
                 <h4>ZoneID:     {{item.ZoneID}}</h4>
              </template>
              <template is='dom-if' if='{{!_show(item.Type)}}'>
                 <h4>BuildingID: {{item.BuildingID}}</h4>
                 <h4>Address1:   {{item.Address1}}</h4>
                 <h4>Address2:   {{item.Address2}}</h4>
               </template>
            </div>
          </paper-card>
        </template>

....

  _show(it){
       return (it === "Zone");
  }

具有以上邏輯應該可以解決問題。