用HTML和Javascript排序表格-第一欄的問題

Question

我使用此代碼創建了可以排序的表： https : //www.w3schools.com/howto/tryit.asp?filename=tryhow_js_sort_table_desc

我的問題是，第2、3和4列將毫無問題地進行排序，但第一個不是。 基本上，如果我按照示例進行操作，則始終是排序的下一列，而不是我單擊的列。 因此，我使用n-1而不是n調整了腳本以過濾適當的列，但是這阻止了我過濾第一個。 我不知道這個問題是從哪里來的。

<div>

    <table id="myTable">
            <colgroup>
           <col span="1" style="width: 45%;">
           <col span="1" style="width: 20%;">
           <col span="1" style="width: 20%;">
           <col span="1" style="width: 20%;">
            </colgroup>
      <tr>
       <!--When a header is clicked, run the sortTable function, with a parameter, 0 for sorting by names, 1 for sorting by country:-->  
        <th onclick="sortTable(0)">Scenario</th>
        <th onclick="sortTable(0)">Delta returns</th>
        <th onclick="sortTable(1)">Sensitivity</th>
        <th onclick="sortTable(2)">Delta volatility</th>
      </tr>
      <tr>
        <th>Scenario 1</th>
        <td>2</td>
        <td>3</td>
        <td>4</td>
      </tr>
      <tr>
        <th>Scenario 2</th>
        <td>7</td>
        <td>1</td>
        <td>5</td>
      </tr>
      <tr>
        <th>Scenario 3</th>
        <td>5</td>
        <td>1</td>
        <td>0</td>
      </tr>
      <tr>
        <th>Scenario 4</th>
        <td>0</td>
        <td>2</td>
        <td>7</td>
      </tr>

    </table>

</div>

劇本。

<script>
function sortTable(n) {
  var table, rows, switching, i, x, y, shouldSwitch, dir, switchcount = 0;
  table = document.getElementById("myTable");
  switching = true;
  //Set the sorting direction to ascending:
  dir = "asc"; 
  /*Make a loop that will continue until
  no switching has been done:*/
  while (switching) {
    //start by saying: no switching is done:
    switching = false;
    rows = table.getElementsByTagName("TR");
    /*Loop through all table rows (except the
    first, which contains table headers):*/
    for (i = 1; i < (rows.length - 1); i++) {
      //start by saying there should be no switching:
      shouldSwitch = false;
      /*Get the two elements you want to compare,
      one from current row and one from the next:*/
      x = rows[i].getElementsByTagName("TD")[n-1];
      y = rows[i + 1].getElementsByTagName("TD")[n-1];
      /*check if the two rows should switch place,
      based on the direction, asc or desc:*/
      if (dir == "asc") {
        if (x.innerHTML.toLowerCase() > y.innerHTML.toLowerCase()) {
          //if so, mark as a switch and break the loop:
          shouldSwitch= true;
          break;
        }
      } else if (dir == "desc") {
        if (x.innerHTML.toLowerCase() < y.innerHTML.toLowerCase()) {
          //if so, mark as a switch and break the loop:
          shouldSwitch= true;
          break;
        }
      }
    }
    if (shouldSwitch) {
      /*If a switch has been marked, make the switch
      and mark that a switch has been done:*/
      rows[i].parentNode.insertBefore(rows[i + 1], rows[i]);
      switching = true;
      //Each time a switch is done, increase this count by 1:
      switchcount ++;      
    } else {
      /*If no switching has been done AND the direction is "asc",
      set the direction to "desc" and run the while loop again.*/
      if (switchcount == 0 && dir == "asc") {
        dir = "desc";
        switching = true;
      }
    }
  }
}
</script>

和相關的CSS：

table {
    border-collapse: collapse;
    border-spacing: 0;
    height:400px;
    border: 1px solid #ddd;
    overflow-y: scroll;
    overflow-x: scroll;
    display: block;
    font-family: helvetica;
    font-size:12px;
}

th, td {
    text-align: left;
    padding: 8px;
}

tr:nth-child(even){background-color: #002560;
    color:white;
}

th {
    cursor: pointer;
}

Answer 1

您正在使用getElementsByTagName但是每行的第一個單元格是TH元素。 不考慮TH，因此您無法對其進行過濾，並且索引偏離1，因為第0列將是第一個TD元素（這是您的第二列）。 您可以用TD替換TH並使用普通索引（ n而不是n - 1 ）。

或者，您可以使用children來代替getElementsByTagName ，這將返回所有子項，無論其標記名稱是什么。 同樣在這里，使用普通索引（第一列為0，第二列為1，依此類推）。

https://developer.mozilla.org/zh-CN/docs/Web/API/ParentNode/children

像這樣：

x = rows[i].children[n];
y = rows[i + 1].children[n];

Answer 2

嘗試從0開始而不是從1開始。