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MySQL不同的總和,按

[英]Mysql distinct sum, group by

這是我的桌子:

id  user_id   type   value

1   1         type1     2
2   2         type1     1
3   1         type2     5
4   1         type1     2

我想要這樣的輸出:

  user_id   type1   type2
    1         4     5
    2         1     0

請幫忙

您可以這樣嘗試:

SELECT 
    user_id, 
    sum( if( type = 'type1', value, 0 ) ) AS type1,  
    sum( if( type = 'type2', value, 0 ) ) AS type2
FROM 
    table_name 
GROUP BY 
    user_id;

我想,這就是您要搜索的內容:

select 
   user_id,
   (select sum(value) from <yourtablename> sub1 where type = 'type1' where sub1.user_id = baseTable.user_id) as type1,
   (select sum(value) from <yourtablename> sub2 where type = 'type2' where sub2.user_id = baseTable.user_id) as type2,
from
   <yourtablename> baseTable

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