SQL選擇多列中存在的多個值

Question

我有兩個表DiagnosisCodes和DiagnosisConditions，如下所示。 我需要找到患有高血壓和糖尿病的成員（ID）。 這里的問題是DiagnosisCodes分布在10列。 如何檢查該成員是否符合這兩個條件

DiagnosisCodes

+----+-------+-------+-------+-----+--------+
| ID | Diag1 | Diag2 | Diag3 | ... | Diag10 |
+----+-------+-------+-------+-----+--------+
| A  |  2502 |  2593 | NULL  | ... | NULL   |
| B  |  2F93 |  2509 | 2593  | ... | NULL   |
| C  |  C257 |  2509 | C6375 | ... | NULL   |
+----+-------+-------+-------+-----+--------+

DiagnosisConditions

+------+--------------+
| Code |  Condition   |
+------+--------------+
| 2502 | Hypertension |
| 2593 | Diabetes     |
| 2509 | Diabetes     |
| 2F93 | Hypertension |
| 2673 | HeartFailure |
+------+--------------+

預期結果

+---------+
| Members |
+---------+
| A       |
| B       |
+---------+

如何查詢以檢查多列中存在的多個值。 你建議使用EXISTS嗎？

SELECT DISTINCT id 
FROM   diagnosiscodes 
WHERE  ( diag1, diag2...diag10 ) IN (SELECT code 
                                     FROM   diagnosiscondition 
                                     WHERE  condition IN ( 'Hypertension','Diabetes' ) 
                                     ) 

Answer 1

我會使用group by和having來做到這一點：

select dc.id
from diagnosiscodes dc join
     diagnosiscondistions dcon
     on dcon.code in (dc.diag1, dc.diag2, . . . )
group by id
having sum(case when dcon.condition = 'diabetes' then 1 else 0 end) > 0 and
       sum(case when dcon.condition = 'Hypertension' then 1 else 0 end) > 0;

然后，您應該修復您的數據結構。 具有由數字區分的相同信息的單獨列通常是不良數據結構的標志。 你應該有一個表，稱為somethhing像PatientDiagnoses與每名患者和診斷一行。

Answer 2

這是通過取消數據的一種方式

SELECT DISTINCT id
FROM   yourtable
       CROSS apply (VALUES (Diag1),(Diag2),..(Diag10))tc(Diag)
WHERE  Diag IN (SELECT code
                FROM   diagnosiscondition
                WHERE  condition IN ( 'Hypertension', 'Diabetes' ) group by code having count(distinct condition)=2)