錯誤的布爾值語句未插入數據庫

Question

我有一個看起來像這樣的JSON數組：

{
    "operation": "update_original_team_member",
    "teamMember": {
        "teamMemberPresent": false,
        "unique_id": "5a5b7f6b835408.50059003",
        "user_unique_id": "59bea8b7d56a63.33388595"
    }
}

並且我試圖將其插入到mySQL數據庫中，但是每次都會失敗，但是當我將false更改為true時，它可以工作，為什么這是什么主意？

它插入到的表如下：

CREATE TABLE team_member (
    team_member_id int(11) NOT NULL AUTO_INCREMENT,
    unique_id varchar(23) NOT NULL,
    fullName varchar(50) NOT NULL,
    user_unique_id varchar(23) NOT NULL,
    present boolean NOT NULL,
    date_last_present datetime DEFAULT NULL,
    points int(50) NULL,
    team_id int (11) NOT NULL,
     PRIMARY KEY (team_member_id),
     FOREIGN KEY (`team_id`)
    REFERENCES `ocidb_CB9s149919`.`team` (`team_id`)
    );

JSON數組是從Retrofit發送的（Retrofit是Android的REST客戶端），其接收方式如下：

if ($operation == 'update_original_team_member') {

            if (isset($data -> teamMember) && !empty($data -> teamMember)&& isset($data -> teamMember -> teamMemberPresent)
                && isset($data -> teamMember -> unique_id)&& isset($data -> teamMember -> user_unique_id)){

              $teamMember                 = $data             -> teamMember;
              $teamMemberPresent          = $teamMember       -> teamMemberPresent;
              $unique_id                  = $teamMember       -> unique_id;
              $user_unique_id             = $teamMember       -> user_unique_id;


              echo $fun -> updatePresent($teamMemberPresent,$unique_id, $user_unique_id);

              } else {


              echo $fun -> getMsgInvalidParam();

            }

這是過去的以下功能：

public function updatePresent($teamMemberPresent,$unique_id, $user_unique_id){

     $db = $this -> db;

     if (!empty ($teamMemberPresent)&& !empty ($unique_id)&& !empty ($user_unique_id)){

         $result = $db -> updatePresent($teamMemberPresent,$unique_id, $user_unique_id);

         if ($result) {

            $response["result"] = "success";
            $response["message"] = "Active Students Have Been Recorded!";
            return json_encode($response);

         } else {

            $response["result"] = "failure";
            $response["message"] = "Unable To Update Details, Please Try Again";
            return json_encode($response);

         }
         } else {

      return $this -> getMsgParamNotEmpty();

            }

}   

我用來更新的查詢是：

public function updatePresent($teamMemberPresent,$unique_id, $user_unique_id){



$sql = "UPDATE team_member SET present = :present WHERE unique_id = :unique_id AND user_unique_id = :user_unique_id";


// Prepare statement
$query = $this ->conn ->prepare($sql);

// execute the query
$query->execute(array(':present' => $teamMemberPresent,':unique_id' => $unique_id, ':user_unique_id' => $user_unique_id));

if ($query) {

return true;        

} else {

return false;

    }
 }

我已經使用郵遞員來嘗試解決問題，並且將其范圍縮小到$teamMemberPresent變量失敗，指出在它為false時它為空，但我不知道為什么。 如前所述，將其設置為true時，查詢工作正常。

任何指導將不勝感激。

Answer 1

在您的updatePresent()函數中，此代碼無法將數據識別為有效數據，並跳過數據庫更新：

if (!empty ($teamMemberPresent)&& !empty ($unique_id)&& !empty ($user_unique_id)){
 ... 

原因是，如果empty($teamMemberPresent)的參數值為false則返回true。

http://php.net/empty說：

如果變量不存在或其值等於FALSE，則將其視為空。

您應該改用isset($teamMemberPresent) 。

這是一個演示：

if (isset($data -> teamMember)
&& !empty($data -> teamMember)
&& isset($data -> teamMember -> teamMemberPresent)
&& isset($data -> teamMember -> unique_id)
&& isset($data -> teamMember -> user_unique_id))
{       
        echo "Should all be OK\n";  

        $teamMember                 = $data             -> teamMember;
        $teamMemberPresent          = $teamMember       -> teamMemberPresent;

        if (!empty($teamMemberPresent)) {
                echo "Confirmed, not empty\n";
        } else {
                echo "Woops! It's empty\n";
        }
}

輸出：

Should all be OK
Woops! It's empty

Answer 2

將您的布​​爾變量強制轉換為int。

$query->execute(array(':present' => (int) $teamMemberPresent,':unique_id' => $unique_id, ':user_unique_id' => $user_unique_id));
// this one -> (int) $teamMemberPresent