簡體   English   中英

重新排列MySQLi查詢的數組結果

[英]Rearrange Array Result of MySQLi Query

我有一個MySQLi查詢,該查詢以json格式從我的數據庫中獲取數據。 現在,我想使用PHP重新排列結果以形成一個新數組。

$conn = new mysqli("localhost", "root", "", "angular");

$out = array();

$sql = "SELECT * FROM members";
$query = $conn->query($sql);

while($row=$query->fetch_array()){
    $out[] = $row;
}

echo json_encode($out);

該查詢的結果是這樣的:

[
  {
    "0": "1",
    "1": "Neovic",
    "2": "Devierte",
    "3": "Silay City",
    "memid": "1",
    "firstname": "Neovic",
    "lastname": "Devierte",
    "address": "Silay City"
  },
  {
    "0": "2",
    "1": "Julyn",
    "2": "Divinagracia",
    "3": "E.B. Magalona",
    "memid": "2",
    "firstname": "Julyn",
    "lastname": "Divinagracia",
    "address": "E.B. Magalona"
  },
  {
    "0": "3",
    "1": "Gemalyn",
    "2": "Cepe",
    "3": "Bohol",
    "memid": "3",
    "firstname": "Gemalyn",
    "lastname": "Cepe",
    "address": "Bohol"
  },
  {
    "0": "4",
    "1": "Tintin ",
    "2": "Demapanag",
    "3": "Talisy City",
    "memid": "4",
    "firstname": "Tintin ",
    "lastname": "Demapanag",
    "address": "Talisy City"
  },
  {
    "0": "5",
    "1": "Tintin ",
    "2": "Devierte",
    "3": "Silay City",
    "memid": "5",
    "firstname": "Tintin ",
    "lastname": "Devierte",
    "address": "Silay City"
  }
]

現在我想要這樣的結果:

[
    firstname: {"Neovic", "Julyn", "Gemalyn", "Tintin", "Tintin"},
    lastname: {"Devierte", "Divinagracia", "Cepe", "Demapanag", "Devierte"}
]

可以在PHP中實現嗎? 任何幫助表示贊賞。

您可以將數據存儲在單獨的數組中:

<?php
$firsts = [] ;
$lasts = [] ;
while ($row = $query->fetch_array()) {
    $firsts[] = $row['firstname'] ;
    $lasts[] = $row['lastname'] ;
}
$out = ['firstname' => $firsts, 'lastname' => $lasts] ;
?>

1.由於您不需要所有數據,因此請執行以下查詢:

$sql = "SELECT firstname,lastname FROM members";

2.更改如下所示的while循環代碼即可完成:

while($row=$query->fetch_array()){
    $out['firstname'][] = $row['firstname'];
    $out['lastname'][] = $row['lastname'];
}

因此,完整的代碼必須是:

$conn = new mysqli("localhost", "root", "", "angular");

$out = array();

$sql = "SELECT firstname,lastname FROM members";
$query = $conn->query($sql);

while($row=$query->fetch_array()){
    $out['firstname'][] = $row['firstname'];
    $out['lastname'][] = $row['lastname'];
}

echo json_encode($out);
<?php

$i=0;
while ($row = $query->fetch_array())
{
    $user[$i]['first_name'] = $row['firstname'] ;
    $user[$i]['last_name'] = $row['lastname'] ;
   $i++;

 }
json_encode($user);
?>

暫無
暫無

聲明:本站的技術帖子網頁,遵循CC BY-SA 4.0協議,如果您需要轉載,請注明本站網址或者原文地址。任何問題請咨詢:yoyou2525@163.com.

 
粵ICP備18138465號  © 2020-2024 STACKOOM.COM