匹配單詞模式並用R中的NA替換單詞

Question

我在R中有2個數據框-一個名稱列表，另一個是單詞詞典。 如果名稱的任何部分是單詞詞典的一部分，則用NA代替，否則返回名稱

名稱-數據框

Name
Louis
Messi
duplessis
Jegan
Praveen

單詞詞典-數據框

Dictionary
vee
sis

預期產量

Name        Processed_Name
Louis       Louis
Messi       Messi
duplessis   NA
Jegan       Jegan
Praveen     NA

Answer 1

library(data.table) # needed library

# create data
dt <- data.table("Name"=c("Louis",
                          "Messi",
                          "duplessis",
                          "Jegan",
                          "Praveen"))
dict <- c("vee","sis")

# make a combined vector of the words in the dictionary
dict_2 <- paste0(dict,collapse = "|") 
# desired output
dt[,processed_Name:=ifelse(Name%like%dict_2,NA,Name)]

OUTPUT

        Name processed_Name
1:     Louis          Louis
2:     Messi          Messi
3: duplessis             NA
4:     Jegan          Jegan
5:   Praveen             NA

根據OP的評論進行更新

  # changed the input a bit, so that it contains the numbers 
# that i am going to generate for the dictionary.
dt <- data.table("Name"=c("Loui1s",
                          "Messi",
                          "duple2ssis",
                          "Jegan",
                          "Praveen"))

dict_all <- as.character(c(1:5000)) # i generate numbers so that they all are different
dict_split <- split(dict_all, ceiling(seq_along(dict_all)/1000))
dict_split_2 <- lapply(dict_split, function(x){paste0(x, collapse = "|")})
dt[,processed_Name_2:=ifelse(Name%like%dict_split_2[[1]] | Name%like%dict_split_2[[2]] |
                               Name%like%dict_split_2[[3]] | Name%like%dict_split_2[[4]] |
                               Name%like%dict_split_2[[5]],NA,Name)]