[英]Recursive merging of objects in javascript
我目前正在使用React進行項目,使用setState方法合並兩個對象時遇到了問題。 我有兩個對象類似於
person1 = {
name: 'ramya',
age: 21,
gender: 'f',
skills:{
technicalSkills: {
languages: ['C', 'C++', 'Java'],
operatingSystems: ['Unix', 'Linux']
},
linguisticSkills: {
toSpeak: ['English', 'Tamil'],
toRead: ['English']
}
},
}
obj2 = {
skills: {
linguisticSkills: {
toRead: ['English', 'Tamil']
}
}
}
我想將人1的技能狀態更改為
linguisticSkills: {
toSpeak: ['English', 'Tamil'],
toRead: ['English', 'Tamil']
}
skills.linguisticSkills.toSpeak
和skills.linguisticSkills.toRead
保持不變,即添加或刪除項目。 每當發生變化時,如何將set1中的person1和obj2合並,以便最終處於正確的狀態?
更新: _.merge在這種情況下失敗:
person1 = {
name: 'ramya',
age: 21,
gender: 'f',
skills:{
technicalSkills: {
languages: ['C', 'C++', 'Java'],
operatingSystems: ['Unix', 'Linux']
},
linguisticSkills: {
toSpeak: ['English', 'Tamil'],
toRead: ['English', 'Tamil', 'Telugu']
}
},
}
obj2 = {
skills: {
linguisticSkills: {
toRead: ['English', 'Tamil']
}
}
}
它給出的結果與人1相同,而
{
name: 'ramya',
age: 21,
gender: 'f',
skills:{
technicalSkills: {
languages: ['C', 'C++', 'Java'],
operatingSystems: ['Unix', 'Linux']
},
linguisticSkills: {
toSpeak: ['English', 'Tamil'],
toRead: ['English', 'Tamil']
}
},
}
是期待。
Lodash的_.merge()
是遞歸的。 如果您需要有關合並過程的更精細控制,則可以使用_.mergeWith()
。
const person1 = {"name":"ramya","age":21,"gender":"f","skills":{"technicalSkills":{"languages":["C","C++","Java"],"operatingSystems":["Unix","Linux"]},"linguisticSkills":{"toSpeak":["English","Tamil"],"toRead":['English', 'Tamil', 'Telugu']}}} const obj2 = {"skills":{"linguisticSkills":{"toRead":["English","Tamil"]}}} const result = _.mergeWith({}, person1, obj2, (objValue, srcValue) => { if( _.isArray(srcValue)) { return srcValue; } }); console.log(result);
<script src="https://cdnjs.cloudflare.com/ajax/libs/lodash.js/4.17.4/lodash.min.js"></script>
查看https: 如何進行深度合並而不是淺層合並?
/**
* Simple object check.
* @param item
* @returns {boolean}
*/
export function isObject(item) {
return (item && typeof item === 'object' && !Array.isArray(item));
}
/**
* Deep merge two objects.
* @param target
* @param ...sources
*/
export function mergeDeep(target, ...sources) {
if (!sources.length) return target;
const source = sources.shift();
if (isObject(target) && isObject(source)) {
for (const key in source) {
if (isObject(source[key])) {
if (!target[key]) Object.assign(target, { [key]: {} });
mergeDeep(target[key], source[key]);
} else {
Object.assign(target, { [key]: source[key] });
}
}
}
return mergeDeep(target, ...sources);
}
// Code copied from linked Stack Overflow question
// https://stackoverflow.com/questions/27936772/how-to-deep-merge-instead-of-shallow-merge
// Answer by Salakar:
// https://stackoverflow.com/users/2938161/salakar
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