[英]How to filter JSON data using Typescript / Javascript / Angular 4?
我有這樣的json數據
data :[
{taskname:'chennai', id:'maa' }
{taskname:'mumbai', id:'bom' }
{taskname:'delhi', id:'del' }
....
....
....
{taskname:'salem', id:'che'}
{taskname:'bengaluru', id:'blr'}
{taskname:'chavvapet', id:'chv'}
}]
現在,我需要過濾此數據並返回匹配的值(就像自動完成一樣)。 例如,當我獲得值CH時 ,首先需要檢查ID ,然后檢查taskname 。 所以返回值應該是這樣的。 必須先將ID匹配到top,然后再匹配taksname。
{taskname:'salem', id:'che'}
{taskname:'chavvapet', id:'chv'}
{taskname:'chennai', id:'maa'}
如果我得到值CHE,那么我需要像這樣返回值
{taskname:'salem', id:'che' }
{taskname:'chennai', id:'maa' }
有人可以告訴我如何使用打字稿進行過濾嗎?
試過這個答案很少 ,但沒有運氣。
試試這個代碼
const data = [ {taskname:'chennai', id:'maa',status:'Submitted'}, {taskname:'mumbai', id:'bom',status:'Resolved'}, {taskname:'delhi', id:'del',status:'Submitted'}, {taskname:'salem', id:'che',status:'In Progress'}, {taskname:'bengaluru',id:'blr',status:'Resolved'}, {taskname:'chavvapet',id:'chv',status:'Submitted'} ]; function filterByString(data, s) { return data.filter(e => e.id.includes(s) || e.taskname.includes(s)) .sort((a,b) => a.id.includes(s) && !b.id.includes(s) ? -1 : b.id.includes(s) && !a.id.includes(s) ? 1 :0); } console.log(filterByString(data, "ch"));
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