PHP關聯數組與唯一值合並

Question

我有一個看起來像這樣的數組

$array=Array ( [0] => Array ( [Country] => United Arab Emirates [users] => 2 )
        [1] => Array ( [Country] => Albania [users] => 1 ) 
        [2] => Array ( [Country] => Armenia [users] => 4 ) 
        [3] => Array ( [Country] => Argentina [users] => 12 )
        [4] => Array ( [Country] => United Arab Emirates [users] => 3 ) 
        [5] => Array ( [Country] => Austria [users] => 1 ) 
        [6] => Array ( [Country] => Austria [users] => 8 ) 
        [7] => Array ( [Country] => Austria [users] => 1 ) )

如果第一個值相同，我想添加第二個值。 我試過 array_unique($array) 但如果第一個值相同，則無法添加第二個值。

所以我期望的輸出是

Array ( [0] => Array ( [Country] => United Arab Emirates [users] => 5 )
        [1] => Array ( [Country] => Albania [users] => 1 ) 
        [2] => Array ( [Country] => Armenia [users] => 4 ) 
        [3] => Array ( [Country] => Argentina [users] => 12 )
        [4] => Array ( [Country] => Austria [users] => 10 ))

我嘗試如下但無法解決

$array=array_unique($array)
and 
        foreach ($array as $unique){
            if( in_array( $unique['Country'] ,$array) )
            {
                print_r ($unique['Country']);
            }
        }

你能幫我嗎？

Answer 1

您可以使用array_reduce ，例如：

$sum = array_reduce($data, function ($a, $b) {
    isset($a[$b['Country']]) ? $a[$b['Country']]['users'] += $b['users'] : $a[$b['Country']] = $b;  
    return $a;
});


echo "<pre>"; print_r(array_values($sum));

Answer 2

您可以為此執行經典的foreach循環：

$result = array();

foreach( $array as $value ){
    if( !isset( $result[ $value[ "Country" ] ] ) ) $result[ $value[ "Country" ] ] = $value;
    else $result[ $value[ "Country" ] ][ "users" ] += $value[ "users" ];
}

$result = array_values($result);

這將導致：

Array
(
    [0] => Array
        (
            [Country] => United Arab Emirates
            [users] => 5
        )

    [1] => Array
        (
            [Country] => Albania
            [users] => 1
        )

    [2] => Array
        (
            [Country] => Armenia
            [users] => 4
        )

    [3] => Array
        (
            [Country] => Argentina
            [users] => 12
        )

    [4] => Array
        (
            [Country] => Austria
            [users] => 10
        )

)

Answer 3

您可以簡單地遍歷第一個數組並自己總結它們：

$array = [
    [ "Country" => "United Arab Emirates", "users" => 2 ],
    [ "Country" => "Albania", "users" => 1 ], 
    [ "Country" => "Armenia", "users" => 4 ], 
    [ "Country" => "Argentina", "users" => 12 ],
    [ "Country" => "United Arab Emirates", "users" => 3 ], 
    [ "Country" => "Austria", "users" => 1 ], 
    [ "Country" => "Austria", "users" => 8 ], 
    [ "Country" => "Austria", "users" => 1 ], 
 ];

 $new = [];

 foreach ($array as $item) {
     // Check if we already have added the country to the new array
     if (empty($new[$item['Country']])) {
         // The country doesn't exist, add it
         $new[$item['Country']] = ['Country' => $item['Country'], 'users' => 0]; 
     }

     // Add the amount of users
     $new[$item['Country']]['users'] += $item['users'];
 }

 // Since we used the country as key, we can use array_values() 
 // to get it as an array with numeric indexes again.
 $new = array_values($new);

演示： https : //3v4l.org/ZuUoL

Answer 4

您可以使用此方法制作獨特的

array_unique($associativeArray,SORT_REGULAR);

使用名稱和年齡鍵定義關聯數組$associativeArray 。

 $associativeArray[] = array("name" => "pankaj Singh","no"=>4);
 $associativeArray[] = array("name" => "pankaj Singh","no"=>24);

Answer 5

您可以使用 PHP 函數

    in_array()

試試這個

  $array=array();
  foreach($array as $k=>$v){
  foreach($v as $key=>$value){
    if(!in_array($value, $array)){
    $array[]=$value;
    }
  }
 }

Answer 6

試試這個。 我希望這會幫助你：

$country_users = array();
foreach ($array as $each) {
    $value = $each['users'];
    if (array_key_exists($each['Country'], $country_users)) {
        $prev_users = $country_users[$each['Country']];
        $value = $each['users'] + $prev_users;
    }
    $country_users[$each['Country']] = $value;
}
unset($array);
foreach ($country_users as $country=>$users) {
    $array[] = array('Country' => $country, 'users' => $users);
}
echo '<pre>';
print_r($array);

Answer 7

您將通過以下代碼獲得結果：

$request = array();
    foreach ($yourArray as $key => $value) {
      if (!in_array($value['country'], $request)) {
        $request[] = $value['country'];
      }
      else {
        unset($yourArray[$key]);
      }
    }
    print_r($yourArray);

Answer 8

您可以簡單地使用array_merge_recursive() 、 array_unique() 、 in_array()函數。 正如你在上面看到的建議。 但我的建議是更改數組結構（如果可能），將關聯數組與國家名稱作為鍵並作為值計數。 操作和理解會更簡單明了。

$array = [
    'Austria' => 12,
];

您可以稍后根據需要更改數組結構以進行響應。 但我相信，使用鍵值結構操作可以幫助您避免很多麻煩。