[英]how to fetch data from multiple tables
因此,我對我的數據庫進行了規范化,而獲取或更新表中的記錄對我來說似乎相當復雜。 我有5個表格( details
, country
, materials
, vendor_countries
, vendor_materials
)。 實際上, "details"
是我的主要表。
country
表有兩列( id
, name
)。 materials
表也有兩列( id
, name
)。 details
表包含有關供應商的人員信息( name
, email
, phone
, address
)。 一個供應商可以有多個國家和地區,因此我又創建了兩個表vendor_countries
和vendor_materials
,它們的列是( did
, cid
),( did
, mid
)。 "did"
是來自details
表和cid
的每個供應商的ID, mid
是來自國家和材料表的國家ID和材料ID。
現在,我想獲取供應商及其國家和材料。
這是我的詳細信息表,vendor_countries和vendor_materials表
到目前為止,我進行了查詢,如下所示:
select dt.vendor,
dt.email,
dt.address,
c.country,
m.material,
c.country
from country c
inner join vendor_countries vc on (c.id = vc.cid)
right join details dt on (dt.id = vc.did)
left join vendor_materials vm on dt.id = vm.did
left join material m on vm.mid = m.id
我得到這樣的結果:
這是不對的,應該分成3行,因為“ ali”供應商在3個國家/地區和3種材料下工作。 我正在尋找一些不會降低我的頁面速度的智能解決方案。 提前致謝。
在沒有關於表模式的任何響應的情況下,我嘗試根據上述說明重新創建表-在每個表前加上v_
前綴,以便我可以將該表分組, did
以vid
(vendor id)的方式進行引用,並填充我相信是問題的樣本數據
mysql> describe v_country;
+-------+------------------+------+-----+---------+----------------+
| Field | Type | Null | Key | Default | Extra |
+-------+------------------+------+-----+---------+----------------+
| id | int(10) unsigned | NO | PRI | NULL | auto_increment |
| name | varchar(50) | YES | | NULL | |
+-------+------------------+------+-----+---------+----------------+
mysql> describe v_details;
+---------+------------------+------+-----+---------+----------------+
| Field | Type | Null | Key | Default | Extra |
+---------+------------------+------+-----+---------+----------------+
| id | int(10) unsigned | NO | PRI | NULL | auto_increment |
| vendor | varchar(50) | YES | | NULL | |
| email | varchar(50) | YES | | NULL | |
| phone | varchar(50) | YES | | NULL | |
| address | varchar(50) | YES | | NULL | |
+---------+------------------+------+-----+---------+----------------+
mysql> describe v_materials;
+-------+------------------+------+-----+---------+----------------+
| Field | Type | Null | Key | Default | Extra |
+-------+------------------+------+-----+---------+----------------+
| id | int(10) unsigned | NO | PRI | NULL | auto_increment |
| name | varchar(50) | YES | | NULL | |
+-------+------------------+------+-----+---------+----------------+
mysql> describe v_vendor_materials;
+-------+------------------+------+-----+---------+----------------+
| Field | Type | Null | Key | Default | Extra |
+-------+------------------+------+-----+---------+----------------+
| id | int(10) unsigned | NO | PRI | NULL | auto_increment |
| vid | int(10) unsigned | NO | MUL | 0 | |
| mid | int(10) unsigned | NO | MUL | 0 | |
+-------+------------------+------+-----+---------+----------------+
mysql> describe v_vendor_countries;
+-------+------------------+------+-----+---------+----------------+
| Field | Type | Null | Key | Default | Extra |
+-------+------------------+------+-----+---------+----------------+
| id | int(10) unsigned | NO | PRI | NULL | auto_increment |
| vid | int(10) unsigned | NO | MUL | 0 | |
| mid | int(10) unsigned | NO | MUL | 0 | |
+-------+------------------+------+-----+---------+----------------+
mysql> select * from v_country;
+----+----------+
| id | name |
+----+----------+
| 1 | pakistan |
| 2 | India |
| 3 | Iran |
+----+----------+
mysql> select * from v_details;
+----+--------+------------------+---------------+-----------+
| id | vendor | email | phone | address |
+----+--------+------------------+---------------+-----------+
| 1 | harris | harris@gmail.com | 0141 236 4523 | nowhere |
| 2 | Boris | boris@gmail.com | 0141 451 7845 | somewhere |
| 3 | Doris | doris@gmail.com | 0141 353 7845 | anywhere |
+----+--------+------------------+---------------+-----------+
mysql> select * from v_materials;
+----+---------+
| id | name |
+----+---------+
| 1 | ceramic |
| 2 | iron |
| 3 | plastic |
+----+---------+
mysql> select * from v_vendor_materials;
+----+-----+-----+
| id | vid | mid |
+----+-----+-----+
| 1 | 1 | 1 |
| 2 | 2 | 2 |
| 3 | 3 | 3 |
+----+-----+-----+
mysql> select * from v_vendor_countries;
+----+-----+-----+
| id | vid | mid |
+----+-----+-----+
| 1 | 1 | 1 |
| 2 | 2 | 2 |
| 3 | 3 | 3 |
+----+-----+-----+
mysql> select * from v_details d
left outer join v_vendor_materials vm on vm.vid=d.id
left outer join v_vendor_countries vc on vc.vid=d.id
left outer join v_materials m on m.id=vm.id
left outer join v_country c on c.id=vc.id;
+----+--------+------------------+---------------+-----------+------+------+------+------+------+------+------+---------+------+----------+
| id | vendor | email | phone | address | id | vid | mid | id | vid | mid | id | name | id | name |
+----+--------+------------------+---------------+-----------+------+------+------+------+------+------+------+---------+------+----------+
| 1 | harris | harris@gmail.com | 0141 236 4523 | nowhere | 1 | 1 | 1 | 1 | 1 | 1 | 1 | ceramic | 1 | pakistan |
| 2 | Boris | boris@gmail.com | 0141 451 7845 | somewhere | 2 | 2 | 2 | 2 | 2 | 2 | 2 | iron | 2 | India |
| 3 | Doris | doris@gmail.com | 0141 353 7845 | anywhere | 3 | 3 | 3 | 3 | 3 | 3 | 3 | plastic | 3 | Iran |
+----+--------+------------------+---------------+-----------+------+------+------+------+------+------+------+---------+------+----------+
或者,更具選擇性的查詢
select
d.`id` as `vid`,
d.`vendor`,
d.`email`,
d.`phone`,
d.`address`,
m.`name` as `material`,
c.`name` as `country`
from v_details d
left outer join v_vendor_materials vm on vm.vid=d.id
left outer join v_vendor_countries vc on vc.vid=d.id
left outer join v_materials m on m.id=vm.id
left outer join v_country c on c.id=vc.id;
+-----+--------+------------------+---------------+-----------+----------+----------+
| vid | vendor | email | phone | address | material | country |
+-----+--------+------------------+---------------+-----------+----------+----------+
| 1 | harris | harris@gmail.com | 0141 236 4523 | nowhere | ceramic | pakistan |
| 2 | Boris | boris@gmail.com | 0141 451 7845 | somewhere | iron | India |
| 3 | Doris | doris@gmail.com | 0141 353 7845 | anywhere | plastic | Iran |
+-----+--------+------------------+---------------+-----------+----------+----------+
聲明:本站的技術帖子網頁,遵循CC BY-SA 4.0協議,如果您需要轉載,請注明本站網址或者原文地址。任何問題請咨詢:yoyou2525@163.com.