借助 VBA 組合列中的連續值

Question

我有這樣的數據：

A049
A050
A051
A053
A054
A055
A056
A062
A064
A065
A066

我想要這樣的輸出：

如您所見，我想要連續順序的范圍

我正在嘗試這樣的事情：

Private Sub CommandButton1_Click()

    Set wb = ThisWorkbook
    lastRow = wb.Sheets("Sheet1").Range("A" & wb.Sheets("Sheet1").Rows.Count).End(xlUp).Row
    For i = 2 To lastRow
        r = wb.Sheets("Sheet1").Range("A" & i).Value

        If wb.Sheets("Sheet1").Range("A" & i).Value = wb.Sheets("Sheet1").Range("A" & i+1).Value
    Next i
End Sub

但不幫我

Answer 1

試試下面的代碼

Private Sub CommandButton1_Click()

    Set wb = ThisWorkbook
    lastRow = wb.Sheets("Sheet1").Range("A" & wb.Sheets("Sheet1").Rows.Count).End(xlUp).Row
    Dim lastNum, Binsert As Integer
    Dim firstCell, lastCell, currentCell As String
    Binsert = 1
    lastNum = getNum(wb.Sheets("Sheet1").Range("A1").Value)
    firstCell = wb.Sheets("Sheet1").Range("A1").Value
    For i = 2 To lastRow
        activeNum = getNum(wb.Sheets("Sheet1").Range("A" & i).Value)
        currentCell = wb.Sheets("Sheet1").Range("A" & i).Value
        If (activeNum - lastNum) = 1 Then
            'nothing
        Else
            lastCell = wb.Sheets("Sheet1").Range("A" & (i - 1)).Value
            wb.Sheets("Sheet1").Range("B" & Binsert).FormulaR1C1() = firstCell
            If (firstCell <> lastCell) Then
                wb.Sheets("Sheet1").Range("C" & Binsert).FormulaR1C1() = lastCell
            End If
            Binsert = Binsert + 1
            firstCell = wb.Sheets("Sheet1").Range("A" & i).Value
        End If
        lastNum = activeNum
    Next i
    'last entry
    wb.Sheets("Sheet1").Range("B" & Binsert).FormulaR1C1() = firstCell
    If (firstCell <> currentCell) Then
        wb.Sheets("Sheet1").Range("C" & Binsert).FormulaR1C1() = currentCell
    End If
End Sub
Public Function getNum(ByVal num As String) As Integer
    getNum = Val(Mid(num, 2))
End Function

Answer 2

我感覺很慈善，所以嘗試了一些應該可以工作的代碼。 它假設您的起始值在 A1 中，並將結果放在 C1 中。

Sub x()

Dim v1, v2(), i As Long, j As Long

v1 = Range("A1", Range("A" & Rows.Count).End(xlUp)).Value

ReDim v2(1 To UBound(v1, 1), 1 To 2)

For i = LBound(v1, 1) To UBound(v1, 1)
    j = j + 1
    v2(j, 1) = v1(i, 1)
    If i <> UBound(v1, 1) Then
        Do While Val(Right(v1(i + 1, 1), 3)) = Val(Right(v1(i, 1), 3)) + 1
            i = i + 1
            If i = UBound(v1, 1) Then
                v2(j, 2) = v1(i, 1)
                Exit Do
            End If
        Loop
    End If
    If v1(i, 1) <> v2(j, 1) Then v2(j, 2) = v1(i, 1)
Next i

Range("C1").Resize(j, 2) = v2

End Sub

Answer 3

另一種解決方案。 它從最后一行向后循環到第一行。

Option Explicit

Public Sub FindConsecutiveValues()
    Dim ws As Worksheet
    Set ws = ThisWorkbook.Worksheets("Sheet1")

    Dim lRow As Long 'find last row
    lRow = ws.Range("A" & ws.Rows.Count).End(xlUp).Row

    Dim lVal As String 'remember last value (stop value)
    lVal = ws.Range("A" & lRow).Value

    Const fRow As Long = 2 'define first data row
    Dim i As Long
    For i = lRow To fRow Step -1 'loop from last row to first row backwards
        Dim iVal As Long
        iVal = Val(Right(ws.Range("A" & i).Value, Len(ws.Range("A" & i).Value) - 1)) 'get value of row i without A so we can calculate

        Dim bVal As Long
        bVal = 0 'reset value
        If i <> fRow Then 'if we are on the first row there is no value before
            bVal = Val(Right(ws.Range("A" & i - 1).Value, Len(ws.Range("A" & i - 1).Value) - 1)) 'get value of row i-1 without A
        End If

        If iVal - 1 = bVal Then
            ws.Rows(i).Delete 'delete current row
        Else
            If lVal <> ws.Range("A" & i).Value Then 'if start and stop value are not the same …
                ws.Range("B" & i).Value = lVal 'write stop value in column B
            End If
            lVal = ws.Range("A" & i - 1).Value 'remember now stop value
        End If
    Next i
End Sub