無法過濾嵌套的json對象

Question

我想根據GUI中的用戶輸入，使用procedureName和hospitalName過濾以下json數據。

myObject= [
    {        
        "department": "Gynic",
        "treatmentList": [
            {
                "procedureName": "Bone Grafting",               
                "hospitalList": [
                    {
                        "hospitalName": "Renai",                        
                    },
                    {
                        "hospitalName": "Aster",                        
                    },
                    {
                        "hospitalName": "Appolo",                        
                    }
                ],                
            },
            {                
                "procedureName": "IVF",                
                "hospitalList": [
                    {
                        "hospitalName": "Renai",                        
                    }
                ],               
            }
        ]
    }
]

例如，當使用程序名稱“ Bone Grafting”和醫院名稱“ Renai”過濾上述json時，我應以以下格式獲取結果。

     [
    {        
        "department": "Gynic",
        "treatmentList": [
            {
                "procedureName": "Bone Grafting",               
                "hospitalList": [
                    {
                        "hospitalName": "Renai",                        
                    },
                    {
                        "hospitalName": "Aster",                        
                    },
                    {
                        "hospitalName": "Appolo",                        
                    }
                ],                
            }
        ]
    }
]

我嘗試使用下面的代碼，但它沒有過濾json

var x = myObject.filter(function (obj) {
    return obj.treatmentList.some(function (item) {
        return item.procedureName == 'Bone Grafting';
    });
});

有人可以幫助我糾正代碼中的錯誤嗎？

Answer 1

意見

• 您需要遍歷myObject數組。
• 為hospitalList數組添加some函數的新調用，並與hospitalName屬性進行比較。
• 最后，將找到的匹配項添加到您的treatmentList數組中。

 var myObject = [{ "department": "Gynic", "treatmentList": [{ "procedureName": "Bone Grafting", "hospitalList": [{ "hospitalName": "Renai", }, { "hospitalName": "Aster", }, { "hospitalName": "Appolo", } ], }, { "procedureName": "IVF", "hospitalList": [{ "hospitalName": "Renai", }], } ] }]; var myResultObject = []; for (var i = 0; i < myObject.length; i++) { myResultObject.push({ 'department': myObject[i].department, 'treatmentList': myObject[i].treatmentList.filter(function(obj) { return obj.procedureName === 'Bone Grafting' && obj.hospitalList.some(function(hn) { return hn.hospitalName === 'Renai'; }); }) }); } console.log(myResultObject); 

Answer 2

不知道這是否是最好的方法，但是您可以嘗試類似

 var myObject = [{ "department": "Gynic", "treatmentList": [{ "procedureName": "Bone Grafting", "hospitalList": [{ "hospitalName": "Renai", }, { "hospitalName": "Aster", }, { "hospitalName": "Appolo", }], }, { "procedureName": "IVF", "hospitalList": [{ "hospitalName": "Renai", }], }] }]; function search(procedureName, hospitalName) { return myObject[0].treatmentList.filter(e => { if (e.procedureName === procedureName) { return e.hospitalList.filter(h => { return h.hospitalName === hospitalName }) } }) } console.log(search("IVF", "Renai")) 

Answer 3

Array.some只需要數組中的至少一個元素即可通過測試。 因此，filter方法返回true ，而不過濾任何內容。

以下方法可以滿足您的需求。

var x = myObject.map(function (obj) {
    obj.treatmentList = obj.treatmentList.filter(function (item) {
        return item.procedureName == 'Bone Grafting' &&
            item.hospitalList.some(function (hospital) {
                return hospital.hospitalName == 'Renai';
            });
    });
    return obj;
});