SQL Server Query組通過解析

Question

我有這樣的桌子

Id scid  name  namesuffix nameId namesuffixid  fullname
--------------------------------------------------------
1   1    a     a          100    100            a
2   1    a     b          100    101            ab
3   1    b     c          101    102            abc
4   1    c     d          102    103            abcd 
5   2    e     e          104    104            e
6   2    e     f          104    105            ef
7   2    f     g          105    106            efg
8   3    i     i          107    107            i
9   3    i     j          107    108            ij 
10  3    j     k          108    109            ijk
11  3    k     l          109    110            ijkl
12  3    l     m          110    111            ijklm


for each scid (group by scid) 
    select firstRow fullName
         Last row fullName

預期產量

id scid  fullname
-------------------
1  1     a
4  1     abcd
5  2     e
7  2     efg
8  3     i
12 3     ijklm

我嘗試了first_value和last_value分析函數，但是這些行在重復，沒有得到預期的結果。

任何幫助表示贊賞。

Answer 1

您可以按照建議使用FIRST_VALUE和LAST_VALUE ：

SELECT scid,
     FIRST_VALUE(id) OVER(PARTITION BY scid ORDER BY id 
                          ROWS UNBOUNDED PRECEDING) AS id,
     FIRST_VALUE(fullname) OVER(PARTITION BY scid ORDER BY id 
                           ROWS UNBOUNDED PRECEDING) AS fullname
FROM tab_name
UNION 
SELECT scid,
     LAST_VALUE(id) OVER(PARTITION BY scid ORDER BY id 
                   RANGE BETWEEN CURRENT ROW AND UNBOUNDED FOLLOWING) AS id,
     LAST_VALUE(fullname) OVER(PARTITION BY scid ORDER BY id
                   RANGE BETWEEN CURRENT ROW AND UNBOUNDED FOLLOWING) AS fullname
FROM tab_name
ORDER BY scid, id;

演示版

Answer 2

另一種選擇是使用ROW_NUMBER()和COUNT

select
    id, scid, fullname
from (
    select
        *, row_number() over (partition by scid order by id) rn
        , count(*) over (partition by scid) cnt
    from
        myTable
) t
where
    rn = 1 
    or rn = cnt

Answer 3

還有其他沒有窗口功能的方法：

select t.*
from t join
     (select min(id) as min_id, max(id) as max_id
      from t
      group by sc_id
     ) tt
     on t.id in (min_id, max_id);

我只建議這樣做，因為有很多方法可以做您想要的。 如果性能是一個問題，則您可能需要嘗試不同的方法。