javascript如何根據另一個對象數組過濾對象數組

Question

這是示例，請提供等效的javascript代碼幫助

array A = [{id: 1, name:'cat'},{id:2, name:'dog'},{id:3, name:'tiger'}];

array B = [{name:'cat'},{name:'dog'}];

結果

expected = [{id: 1, name:'cat'},{id:2, name:'dog'}];

需要根據陣列B中可用的名稱過濾陣列A

與SQL相似，其中name在('cat','dog') 。

試圖使用array.filter和indexOf !== -1

但是沒有得到預期的結果。

Answer 1

隨着數組變大，構建查找對象可能會更好，但是使用Array.prototype.filter()和Array.prototype.some()的簡單方法可能如下所示：

 const a = [{id: 1, name:'cat'}, {id:2, name:'dog'}, {id:3, name:'tiger'}]; const b = [{name:'cat'}, {name:'dog'}]; const result = a.filter(x => b.some(y => x.name === y.name)); console.log(result); 

Answer 2

  const a = [{id: 1, name:'cat'}, {id:2, name:'dog'}, {id:3, name:'tiger'}]; const b = [{name:'cat'}, {name:'dog'}]; var res = a.filter((per)=>b.find((x)=>per.name===x.name)) console.log(res)