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如何將列表對象中的字符串與另一個普通字符串進行比較

[英]How to compare a string from a list object with a another normal string

原文 2018-01-29 09:32:59 0 1 java/ spring/ spring-data-jpa

我有一個List對象，我想檢查所有重復的名稱，同時保存到下面的db中是我的代碼，但是它不起作用：

List<ChartOfAccount> checkDuplicateDetails = accountTypeRepository.checkDuplicateDetails();
    for (ChartOfAccount chartOfAccDuplicate: checkDuplicateDetails) {   
      if(chartOfAccDuplicate.getAccountName().equals("hello123")){
        System.out.println("found duplicate");
      }else {               
        chartOfAccRepository.save(chartOfAccount);
      }
    }

1 個解決方案

有兩種可能性

您的chartOfAccDuplicate.getAccountName（）方法未返回字符串 litereal
或者您必須使用chartOfAccDuplicate.getAccountName（）。 equalsIgnoreCase （“ hello123”）

如何創建列表<object>帶有字段字符串和 Map <string, set<string> > 從另一個列表<object2><div id="text_translate"><p> Class Object2具有標准的 getter 並具有String字段folder 、 file和version 。它被命名為SourceInfo</p><p> List<SourceInfo> source包含上面提到的三個字段。</p><p> 我的目標是從List<SourceInfo>創建一個List<Info> > 。</p><p> 新List的 class 為Info ，如下圖所示。</p><pre> public class Info { private final String folder; private final Map<String, Set<String>> file; public static Builder builder() { return new Builder(); } public static Builder builder(Info info) { return new Builder(info); } private Info(Builder builder) { this.folder = builder.folder; this.file = builder.file; } public String getFolder() { return folder; } public Map<String, Set<String>> getFile() { return file; } // autogenerated toString, hashCode, and equals public static class Builder { private String folder; private Map<String, Set<String>> file; private Builder() {} private Builder(Info info) { this.folder = info.folder; this.file = info.file; } public Builder with(Consumer<Builder> consumer) { consumer.accept(this); return this; } public Builder withFolder(String folder) { this.folder = folder; return this; } public Builder withFile(Map<String, Set<String>> file) { this.file = file; return this; } public Info build() { return new Info(this); } }</pre><p> 到目前為止，我嘗試的是在構建器模式中創建一個集合。</p><pre> List<SourceInfo> source; // error: gc overhead limit exceeded List<Info> infoList = source.stream().map(e -> Info.builder().withFolder(e.getFolder()).withFile(source.stream().collect(Collectors.groupingBy(SourceInfo::getKey, Collectors.mapping(SourceInfo::getVersion, Collectors.toSet())))).build()).collect(Collectors.toList()); Map<String, Set<String>> map = source.stream().collect(Collectors.groupingBy(SourceInfo::getKey, Collectors.mapping(SourceInfo::getVersion, Collectors.toSet()))); List<Info> info = source.stream().map(e -> Info.builder().withFolder(e.getFolder()).withFile(map.entrySet().stream().collect(Collectors.toMap(Map.Entry::getKey, Map.Entry::getValue))).build()).collect(Collectors.toList());</pre><p> 所需的 output。以下語法可能已關閉。</p><pre> // [String, Map<String, Set<String>>] Info [folder, [key=file [value=version]]]...</pre><p> 我是 Java 的新手，不勝感激。</p><p> 我想了解如何使用 java8 和 for 循環來做到這一點。</p><p> 謝謝你。</p></div></object2></string,></object>

[英]How to create a List<Object> with fields String and Map<String, Set<String>> from another List<Object2>

如何比較（包含）Object [] []到字符串並將其值添加到另一個Object [] []

[英]How to compare(contains) Object[][] to string and add its values to another Object[][]

如何將方法返回的字符串與主方法中的另一個字符串進行比較？

[英]How to compare a returned string from a method with another string in the main method?

如何將值從 Excel 單元格格式化的字符串變量與普通字符串變量進行比較？

[英]How to compare a string variable whose value is formatted from an excel cell with a normal string variable?

比較列表中字符串的日期

[英]Compare dates from a String in list

如何從HashMap獲取列表 <String,List<String> >到另一個列表

[英]How to fetch list from HashMap <String,List<String>> to another list

如何比較包含字符串的對象？

[英]How to compare an object containing a string?

是否可以將數組字符串與普通字符串進行比較？

[英]Is it possible to compare an array string to a normal string?

如何比較兩個HashMap <String, List<String> >

[英]how to compare two HashMap<String, List<String>>

對象的字符串列表

[英]String list from Object

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相關問題 如何創建列表<object>帶有字段字符串和 Map <string, set<string> > 從另一個列表<object2><div id="text_translate"><p> Class Object2具有標准的 getter 並具有String字段folder 、 file和version 。它被命名為SourceInfo</p><p> List<SourceInfo> source包含上面提到的三個字段。</p><p> 我的目標是從List<SourceInfo>創建一個List<Info> > 。</p><p> 新List的 class 為Info ，如下圖所示。</p><pre> public class Info { private final String folder; private final Map<String, Set<String>> file; public static Builder builder() { return new Builder(); } public static Builder builder(Info info) { return new Builder(info); } private Info(Builder builder) { this.folder = builder.folder; this.file = builder.file; } public String getFolder() { return folder; } public Map<String, Set<String>> getFile() { return file; } // autogenerated toString, hashCode, and equals public static class Builder { private String folder; private Map<String, Set<String>> file; private Builder() {} private Builder(Info info) { this.folder = info.folder; this.file = info.file; } public Builder with(Consumer<Builder> consumer) { consumer.accept(this); return this; } public Builder withFolder(String folder) { this.folder = folder; return this; } public Builder withFile(Map<String, Set<String>> file) { this.file = file; return this; } public Info build() { return new Info(this); } }</pre><p> 到目前為止，我嘗試的是在構建器模式中創建一個集合。</p><pre> List<SourceInfo> source; // error: gc overhead limit exceeded List<Info> infoList = source.stream().map(e -> Info.builder().withFolder(e.getFolder()).withFile(source.stream().collect(Collectors.groupingBy(SourceInfo::getKey, Collectors.mapping(SourceInfo::getVersion, Collectors.toSet())))).build()).collect(Collectors.toList()); Map<String, Set<String>> map = source.stream().collect(Collectors.groupingBy(SourceInfo::getKey, Collectors.mapping(SourceInfo::getVersion, Collectors.toSet()))); List<Info> info = source.stream().map(e -> Info.builder().withFolder(e.getFolder()).withFile(map.entrySet().stream().collect(Collectors.toMap(Map.Entry::getKey, Map.Entry::getValue))).build()).collect(Collectors.toList());</pre><p> 所需的 output。以下語法可能已關閉。</p><pre> // [String, Map<String, Set<String>>] Info [folder, [key=file [value=version]]]...</pre><p> 我是 Java 的新手，不勝感激。</p><p> 我想了解如何使用 java8 和 for 循環來做到這一點。</p><p> 謝謝你。</p></div></object2></string,></object> 如何比較（包含）Object [] []到字符串並將其值添加到另一個Object [] [] 如何將方法返回的字符串與主方法中的另一個字符串進行比較？如何將值從 Excel 單元格格式化的字符串變量與普通字符串變量進行比較？比較列表中字符串的日期如何從HashMap獲取列表 <String,List<String> >到另一個列表如何比較包含字符串的對象？是否可以將數組字符串與普通字符串進行比較？如何比較兩個HashMap <String, List<String> > 對象的字符串列表

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