左連接不返回所有行 Mysql

Question

我有一張有溫室信息的表

pr_grouper_details

--------------------------------------------------------
  id  |  grouper_detail | status | periphery | id_tenant
--------------------------------------------------------
  1   |       1         |   100  |     0     |    1    
-------------------------------------------------------
  1   |       2         |   100  |     0     |    1    
-------------------------------------------------------
  1   |       3         |   100  |     0     |    1    
-------------------------------------------------------
  1   |       4         |   100  |     0     |    1    
-------------------------------------------------------

我有一張桌子，上面有每個溫室的播種：

---------------------------------------------------------
  id  |  id_grouper_detail  | id_product  | type | status
---------------------------------------------------------
  1   |          1          |    1        |  SW  |  100
-------------------------------------------------------- 
  1   |          1          |    2        |  SW  |  100
-------------------------------------------------------- 
  1   |          2          |    1        |  SW  |  100
-------------------------------------------------------- 
  1   |          3          |    1        |  SW  |  100
-------------------------------------------------------- 

這是包含產品信息的表格：

----------------------------
 id  |   product  | status |
----------------------------
  1  |   FLOWER1  |  100   |
---------------------------- 
  2  |   FLOWER2  |  100   |
---------------------------- 

不管你有沒有產品，我都要帶上所有的溫室，但只帶我有產品的：

SELECT id, grouper_detail, GROUP_CONCAT(product SEPARATOR ' - ') AS products
FROM(
                    SELECT pr_grouper_details.id, pr_grouper_details.grouper_detail, pr_products.product
     FROM sw_sowing
                    INNER JOIN pr_products ON pr_products.id = sw_sowing.id_product
     LEFT JOIN pr_grouper_details ON pr_grouper_details.id = sw_sowing.id_grouper_detail
     AND pr_grouper_details.status = 100
     AND pr_grouper_details.periphery = 0
                    AND pr_grouper_details.id_tenant = 1
                    WHERE sw_sowing.type = 'SW'
                    AND sw_sowing.status = 100
                    GROUP BY pr_grouper_details.id, pr_products.id
) AS s
GROUP BY id

這是結果

----------------------------------------------
  id |   grouper_detail |  products 
----------------------------------------------
  1  |         1        |  FLOWER1 - FLOWER2  
----------------------------------------------
  2  |         2        |  FLOWER1  
----------------------------------------------
  3  |         3        |  FLOWER1  
----------------------------------------------

但我需要這樣的東西：

----------------------------------------------
  id |   grouper_detail |  products 
----------------------------------------------
  1  |         1        |  FLOWER1 - FLOWER2  
----------------------------------------------
  2  |         2        |  FLOWER1  
----------------------------------------------
  3  |         3        |  FLOWER1  
----------------------------------------------
  4  |         4        |  NULL  
----------------------------------------------

我正在使用LEFT JOIN但它不起作用，我希望你能幫助我！

Answer 1

使用表別名會更容易跟蹤您的子查詢。 您在ON子句中設置了正確的過濾條件。 但是，您正在按pr_grouper_details.id進行聚合，這可能是NULL 。

而是使用等效的列s.id_grouper_detail 。 然后，我認為您需要從pr_grouper_details開始，因為您想保留所有這些行。 ON和WHERE子句需要調整：

SELECT s.id_grouper_detail, p.product
FROM pr_grouper_details gd LEFT JOIN
     sw_sowing s
     ON gd.id = s.id_grouper_detail AND
        s.type = 'SW' AND
        s.status = 100 LEFT JOIN
     pr_products p
     ON p.id = s.id_product
WHERE gd.status = 100 AND
      gd.periphery = 0 AND
      gd.id_tenant = 1
GROUP BY s.id_grouper_detail, p.product;

您的原始查詢中有gd.id 這是一個壞主意。

Answer 2

試試這個：

SELECT gd.grouper_detail, GROUP_CONCAT(product SEPARATOR ' - ') AS products
FROM pr_grouper_details gd LEFT JOIN
    sw_sowing s
ON gd.grouper_detail = s.id_grouper_detail AND
    s.type = 'SW' AND
    s.status = 100 LEFT JOIN
    pr_products p
ON p.id = s.id_product
WHERE gd.status = 100 AND
    gd.periphery = 0 AND
    gd.id_tenant = 1
GROUP BY s.id_grouper_detail