使用Android中的其余Web服務進行密碼驗證

Question

在這里，我遇到密碼驗證問題，即我輸入正確的密碼時卻說密碼不正確。 在這里我正在使用其余的Web服務，下面是我的代碼，請幫助我。

 EditText password;
   String Passwordstr;
   Button btn_go;    
@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main2);  
    password = (EditText) findViewById(R.id.passET);    
    btn_go = (Button) findViewById(R.id.btn_go);    
    btn_go.setOnClickListener(new View.OnClickListener() {
        @Override
        public void onClick(View v) {
            Passwordstr = password.getText().toString();
            if (Passwordstr.isEmpty()) {
                Toast.makeText(Main2Activity.this, "Please, Enter Your Password.", Toast.LENGTH_SHORT).show();
            } else {

                new MyAsyncTask().execute(Passwordstr);
            }
        }
    });

}    
private class MyAsyncTask extends AsyncTask<String, Integer, String> {

    @Override
    protected String doInBackground(String... params) {    
        String res = PostData(params);    
        return res;
    }

    public String PostData(String[] args) {
        String s = "";

        try {
            HttpClient httpClient = new DefaultHttpClient();
            HttpPost httpPost = new HttpPost("http://localhost:82/demo/login.php");

            HttpResponse httpResponse = httpClient.execute(httpPost);

            HttpEntity httpEntity = httpResponse.getEntity();
            s = readResponse(httpResponse);

        } catch (Exception exception) {
        }

        return s;

    }

    protected void onPostExecute(String result) {

        if (result.equals("true")) {
            Intent intent = new Intent(Main2Activity.this, Main3Activity.class);
          intent.putExtra("Password", Passwordstr);                               
            startActivity(intent);
        } else {
            Toast.makeText(getApplicationContext(), "Password incorrect", Toast.LENGTH_LONG).show();

        }
    }

    public String readResponse(HttpResponse res) {
        InputStream is = null;
        String return_text = "";

        try {
            is = res.getEntity().getContent();
            BufferedReader bufferedReader = new BufferedReader(new InputStreamReader(is));
            String line = "";
            StringBuffer sb = new StringBuffer();
            while ((line = bufferedReader.readLine()) != null) {
                sb.append(line);
            }
            return_text = sb.toString();
        } catch (Exception e) {

        }
        return return_text;
    }
}
}

我正在開發一個Android應用程序，目的是通過Web服務器連接到網頁，這里我使用的是Rest調用和Java代碼。請幫助我。

Answer 1

在您的帖子執行中，您必須像這樣檢查null值而不是true值

 protected void onPostExecute(String result) {

        if (result!=null) {
            Intent intent = new Intent(Main2Activity.this, Main3Activity.class);
          intent.putExtra("Password", Passwordstr);
            //No Full Name
            //MyHomeActivity.putExtra("GetDisplayName",user.getDisplayName());
            //  MyHomeActivity.putExtra("GetPhotoUrl",user.getPhotoUrl());
            startActivity(intent);
        } else {
            Toast.makeText(getApplicationContext(), "Password incorrect", Toast.LENGTH_LONG).show();
            // Hide the progress bar
            //  progressBar.setVisibility(View.GONE);
        }
    }

Answer 2

請嘗試執行此操作，因為您沒有使用鍵和值創建發布參數對。

列表名稱ValuePair = new ArrayList（1）; nameValuePair.add（new BasicNameValuePair（“ password”，“ password”）））;

httpPost.setEntity（new UrlEncodedFormEntity（nameValuePair））; HttpResponse響應= httpClient.execute（httpPost）;

還可以使用相同的密碼從郵遞員或hurl.it中訪問rest api並檢查響應。

Answer 3

您可以使用android-async-http簡單，快速

並且您可以訪問UI線程和響應方法上的視圖

 RestClient.get("statuses/public_timeline.json", null, new JsonHttpResponseHandler() {
        @Override
        public void onSuccess(int statusCode, Header[] headers, JSONObject response) {
            // If the response is JSONObject instead of expected JSONArray
        }

        @Override
        public void onSuccess(int statusCode, Header[] headers, JSONArray timeline) {
            // Pull out the first event on the public timeline
            JSONObject firstEvent = timeline.get(0);
            String Text = firstEvent.getString("text");
             textview.setText(Text);

            // Do something with the response
            System.out.println(tweetText);
        }
    });