井字游戲與python中的數字

Question

我有硬件，這是帶有數字的井字游戲。 顯示一個3 x 3的棋盤，玩家1拿到奇數1、3、5、7、9，而玩家2拿到偶數0、2、4、6、8。玩家輪流寫下他們的數字。 奇數開始。 每個數字只能使用一次。 獲勝者將是第一個完成最多15條路線的人。 該行可以同時具有奇數和偶數。

我一直到這里

board = [0,1,2,
         3,4,5,
         6,7,8]


def tic_tac_toe ():

 print ('|' ,board[0],'|',board[1] ,'|', board[2],'|')

 print ('--------------------')

 print ('|' ,board[3],'|',board[4] ,'|', board[5],'|')

 print ('--------------------')

 print ('|' ,board[6],'|',board[7] ,'|', board[8],'|')


def move(x1,x2):

 board[x2] = x1

     tic_tac_toe()



def odd (x):

    while  (x%2==0):

        x = int(input ('enter an odd number')

        move(x,x2)

    if (x%2!=0):

        move (x ,x2)        



def even (x) :

     while  (x%2!=0):

        x = int(input ('enter an even number')

        move(x,x2)


     if (x%2==0):

        move (x ,x2)        


def winner ():

    if (board[0]+board [1]+board[2]==15 or

        board[0]+board [3]+board[6]==15 or

        board[1]+board [4]+board[7]==15 or

        board[3]+board [4]+board[5]==15 or

        board[2]+board [5]+board[8]==15 or

        board[6]+board [7]+board[8]==15):

        print ('you are the winner')

def turn(s):

    print ('its '+ s +' turn')

    x = int (input ('enter the number: '))
    x1 = int (input ('enter the places number: '))            


print('Tic Tac Toe')

print ('player A should enter even numbers only'+' and player B should enter odd 
numbers only')

print ('the player with the ood numbers start')

tic_tac_toe ()

while (true):

    turn(B)

    odd(x1)
    break    

我現在的問題是，我想創建一個函數來檢查玩家每次輸入數字是否有贏家，我希望它知道已輸入的數字與已經存在的數字之間的差（職位），而且我真的是編程新手，如果代碼有很多錯誤，請原諒

Answer 1

嘗試這個：

我添加了一個董事會日志陣列來監視哪些位置包含用戶輸入，然后在獲勝者功能中交叉引用所述陣列以驗證獲勝條件

board = [0,1,2,
     3,4,5,
     6,7,8]
boardLog = [0, 0, 0,
        0, 0, 0,
        0, 0, 0]

player = 'a' #with this we'll know which player's turn it is

def tic_tac_toe ():
    print ('|' ,board[0],'|',board[1] ,'|', board[2],'|')
    print ('--------------------')
    print ('|' ,board[3],'|',board[4] ,'|', board[5],'|')
    print ('--------------------')
    print ('|' ,board[6],'|',board[7] ,'|', board[8],'|')

def move(x1,x2):
    board[x2] = x1
    boardLog[x2] = 1
    tic_tac_toe()

def odd (x, x2):
    while  (x%2==0):
        x = int(input ('enter an odd number'))
    #Nothing here because if we get out of the while is because it's a valid number (we're not checking numbers out of range or anything)
    move (x ,x2)      

def even (x ,x2) :
    while  (x%2!=0):
        x = int(input ('enter an even number'))
    #Same here
    move (x ,x2)        

def winner():
    if (boardLog[0] + boardLog[1] + boardLog[2] == 3):
      if (board[0]+board [1]+board[2]==15):
          print ('you are the winner')
          return True
    if (boardLog[0] + boardLog[3] + boardLog[6] == 3):
      if (board[0]+board [3]+board[6]==15):
          print ('you are the winner')
          return True
    if (boardLog[1] + boardLog[4] + boardLog[7] == 3):
      if (board[1]+board [4]+board[7]==15):
          print ('you are the winner')
          return True
    if (boardLog[3] + boardLog[4] + boardLog[5] == 3):
      if (board[3]+board [4]+board[5]==15):
          print ('you are the winner')
          return True
    if (boardLog[2] + boardLog[5] + boardLog[8] == 3):
      if (board[2]+board [5]+board[8]==15):
          print ('you are the winner')
          return True
    if (boardLog[6] + boardLog[7] + boardLog[8] == 3):
      if (board[6]+board [7]+board[8]==15):
          print ('you are the winner')
          return True

    else: return False

def turn(s):
    print ('its '+ s +' turn')
    x = int (input ('enter the number: '))
    x1 = int (input ('enter the places number: '))
    if player == 'a':
        even(x, x1)
    else: odd(x, x1)          

print('Tic Tac Toe')
print ('player A should enter even numbers only'+' and player B should enter odd numbers only')
print ('the player with the ood numbers start')
tic_tac_toe ()
while (True):
    turn(player)
    if winner(): break
    else:
        if player == 'a': player = 'b'

Answer 2

我認為這接近您想要的。 注意評論。 還知道我還沒有測試過，我只是更正了您的代碼。 有任何問題請隨時詢問我（們。

board = [0, 0, 0,
         0, 0, 0,
         0, 0, 0]
player = 'a' #with this we'll know which player's turn it is

def tic_tac_toe ():
    print ('|' ,board[0],'|',board[1] ,'|', board[2],'|')
    print ('--------------------')
    print ('|' ,board[3],'|',board[4] ,'|', board[5],'|')
    print ('--------------------')
    print ('|' ,board[6],'|',board[7] ,'|', board[8],'|')

def move(x1,x2):
    board[x2] = x1
    tic_tac_toe()

def odd (x, x2):
    while  (x%2==0):
        x = int(input ('enter an odd number'))
    #Nothing here because if we get out of the while is because it's a valid number (we're not checking numbers out of range or anything)
    move (x ,x2)      

def even (x ,x2) :
    while  (x%2!=0):
        x = int(input ('enter an even number'))
    #Same here
    move (x ,x2)        

def winner ():
    if (board[0]+board [1]+board[2]==15 or
        board[0]+board [3]+board[6]==15 or
        board[1]+board [4]+board[7]==15 or
        board[3]+board [4]+board[5]==15 or
        board[2]+board [5]+board[8]==15 or
        board[6]+board [7]+board[8]==15):
        print ('you are the winner')
        return true #To know if we need to stop the game
    else: return false

def turn(s):
    print ('its '+ s +' turn')
    x = int (input ('enter the number: '))
    x1 = int (input ('enter the places number: '))
    if player == 'a':
        even(x, x1)
    else: odd(x, x1)          

print('Tic Tac Toe')
print ('player A should enter even numbers only'+' and player B should enter odd numbers only')
print ('the player with the ood numbers start')
tic_tac_toe ()
while (true):
    turn(player)
    if winner(): break
    else:
        if player == 'a': player = 'b'
        else: player = 'a'