[英]R data.table add column as function of another data.table
我有一個僅包含時間序列的數據表。 我有另一個包含兩列的數據表:start_time和end_time。 我想獲取第一個數據表並添加一列,該列的值是第二個數據表中所有行的計數,其中第一個數據表中的時間適合開始和結束時間。 這是我的代碼
start_date <- as.POSIXct(x = "2017-01-31 17:00:00", format = "%Y-%m-%d %H:%M:%S")
end_date <- as.POSIXct(x = "2017-02-01 09:00:00", format = "%Y-%m-%d %H:%M:%S")
all_dates <- as.data.table(seq(start_date, end_date, "min"))
colnames(all_dates) <- c("Bin")
start_times <- sample(seq(start_date,end_date,"min"), 100)
offsets <- sample(seq(60,7200,60), 100)
end_times <- start_times + offsets
input_data <- data.table(start_times, end_times)
這是我想做的,但這是錯誤的,並給出了錯誤。 寫這個的正確方法是什么?
all_dates[, BinCount := input_data[start_times < Bin & end_times > Bin, .N] ]
最后我應該得到類似
Bin BinCount
2017-01-31 17:00:00 1
2017-01-31 17:01:00 5
...
使用sqldf
可以很容易地解決該問題,因為它提供了使用范圍檢查sqldf
表的簡便方法。 因此,一種解決方案可能是:
The data from OP:
library(data.table)
start_date <- as.POSIXct(x = "2017-01-31 17:00:00", format = "%Y-%m-%d %H:%M:%S")
end_date <- as.POSIXct(x = "2017-02-01 09:00:00", format = "%Y-%m-%d %H:%M:%S")
all_dates <- as.data.table(seq(start_date, end_date, "min"))
colnames(all_dates) <- c("Bin")
start_times <- sample(seq(start_date,end_date,"min"), 100)
offsets <- sample(seq(60,7200,60), 100)
end_times <- start_times + offsets
input_data <- data.table(start_times, end_times)
library(sqldf)
result <- sqldf("SELECT all_dates.bin, count() as BinCount
FROM all_dates, input_data
WHERE all_dates.bin > input_data.start_times AND
all_dates.bin < input_data.end_times
GROUP BY bin" )
result
Bin BinCount
1 2017-01-31 17:01:00 1
2 2017-01-31 17:02:00 1
3 2017-01-31 17:03:00 1
4 2017-01-31 17:04:00 1
5 2017-01-31 17:05:00 1
6 2017-01-31 17:06:00 1
...........
...........
497 2017-02-01 01:17:00 6
498 2017-02-01 01:18:00 5
499 2017-02-01 01:19:00 5
500 2017-02-01 01:20:00 4
[ reached getOption("max.print") -- omitted 460 rows ]
在data.table
您要進行范圍data.table
。
library(data.table)
start_date <- as.POSIXct(x = "2017-01-31 17:00:00", format = "%Y-%m-%d %H:%M:%S")
end_date <- as.POSIXct(x = "2017-02-01 09:00:00", format = "%Y-%m-%d %H:%M:%S")
all_dates <- as.data.table(seq(start_date, end_date, "min"))
colnames(all_dates) <- c("Bin")
set.seed(123)
start_times <- sample(seq(start_date,end_date,"min"), 100)
offsets <- sample(seq(60,7200,60), 100)
end_times <- start_times + offsets
input_data <- data.table(start_times, end_times)
## doing the range-join and calculating the number of items per bin in one chained step
input_data[
all_dates
, on = .(start_times < Bin, end_times > Bin)
, nomatch = 0
, allow.cartesian = T
][, .N, by = start_times]
# start_times N
# 1: 2017-01-31 17:01:00 1
# 2: 2017-01-31 17:02:00 1
# 3: 2017-01-31 17:03:00 1
# 4: 2017-01-31 17:04:00 1
# 5: 2017-01-31 17:05:00 1
# ---
# 956: 2017-02-01 08:56:00 6
# 957: 2017-02-01 08:57:00 4
# 958: 2017-02-01 08:58:00 4
# 959: 2017-02-01 08:59:00 5
# 960: 2017-02-01 09:00:00 5
注意:
all_dates
對象放在all_dates
的右側,因此即使它們是您的all_dates
,結果也包含input_data
列的名稱(有關此主題的討論,請參閱此問題 ) set.seed()
,因為您正在采樣 不需要,但這是使用tidyverse
的緊湊型替代解決方案。 使用lubridate
解析器, interval
和%within%
以及purrr::map_int
生成所需的bin計數。
library(tidyverse)
library(lubridate)
start_date <- ymd_hms(x = "2017-01-31 17:00:00") # lubridate parsers
end_date <- ymd_hms(x = "2017-02-01 09:00:00")
all_dates <- tibble(seq(start_date, end_date, "min")) # tibble swap for data.table
colnames(all_dates) <- c("Bin")
start_times <- sample(seq(start_date,end_date,"min"), 100)
offsets <- sample(seq(60,7200,60), 100)
end_times <- start_times + offsets
input_data <- tibble(
start_times,
end_times,
intvl = interval(start_times, end_times) # Add interval column
)
all_dates %>% # Checks date in Bin and counts intervals it lies within
mutate(BinCount = map_int(.$Bin, ~ sum(. %within% input_data$intvl)))
# A tibble: 961 x 2
Bin BinCount
<dttm> <int>
1 2017-01-31 17:00:00 0
2 2017-01-31 17:01:00 0
3 2017-01-31 17:02:00 0
4 2017-01-31 17:03:00 0
5 2017-01-31 17:04:00 0
6 2017-01-31 17:05:00 0
7 2017-01-31 17:06:00 0
8 2017-01-31 17:07:00 1
9 2017-01-31 17:08:00 1
10 2017-01-31 17:09:00 1
# ... with 951 more rows
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