[英]django: how to specify database dynamically for factory boy
我正在設置一個包含大量數據庫的Django應用程序,其中一些使用相同的模型(它們不是復制品)。 我已經配置了我的路由器,一切都很好。 在進行測試時會出現問題,因為我想使用factory-boy
。
在一個不同的項目中,我可以在Meta
設置數據庫但現在,我必須選擇在哪個數據庫上動態創建一個實例(如果沒有,我將不得不為每個數據庫創建一個DjangoModelFactory
,這不會很漂亮)。
是否有(更簡單的)方法為每個創建動態指定數據庫?
據我所知, factory_boy
( version <=2.10.0
)沒有提供類似的東西。
但是,您的問題是使用上下文管理器的完美用例。 它允許您在需要的地方動態設置數據庫,並且只在期望的范圍內,並且還可以干!
# factoryboy_utils.py
@classmethod
def _get_manager(cls, model_class):
return super(cls, cls)._get_manager(model_class).using(cls.database)
class DBAwareFactory(object):
"""
Context manager to make model factories db aware
Usage:
with DBAwareFactory(PersonFactory, 'db_qa') as personfactory_on_qa:
person_on_qa = personfactory_on_qa()
...
"""
def __init__(self, cls, db):
# Take a copy of the original cls
self.original_cls = cls
# Patch with needed bits for dynamic db support
setattr(cls, 'database', db)
setattr(cls, '_get_manager', _get_manager)
# save the patched class
self.patched_cls = cls
def __enter__(self):
return self.patched_cls
def __exit__(self, type, value, traceback):
return self.original_cls
然后,在您的測試中,您可以執行以下操作:
from factoryboy_utils import DBAwareFactory
class MyTest(TestCase):
def test_mymodel_on_db1(self):
...
with DBAwareFactory(MyModelFactory, 'db1') as MyModelFactoryForDB1:
mymodelinstance_on_db1 = MyModelFactoryForDB1()
# whatever you need with that model instance
...
# something else here
def test_mymodel_on_db2(self):
...
with DBAwareFactory(MyModelFactory, 'db2') as MyModelFactoryForDB2:
mymodelinstance_on_db2 = MyModelFactoryForDB2()
# whatever you need with that model instance
...
# something else here
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