貓鼬find（{}）不返回任何內容

Question

我想從數據庫中本地分析我的用戶，但是由於某種原因，以下代碼不記錄任何內容，建議嗎？

const mongoose = require('mongoose');
const mongoURIDEV = 'mongodb://MY-URI';
const MONGO = mongoURIDEV;

mongoose.connect(MONGO);
const schema = require('../schema/users');

async function main() {
const users = await schema.find({});
    console.log(users.length);
}

main().catch((e) => {
    console.log(e);
});

編輯：這是使用的架構：

const mongoose = require('mongoose');

const { Schema } = mongoose;

const usersSchema = new Schema({
  id: String,
  uid: String,
  gender: String,
  forward: String,
  keyword: String,
  placeType: String,
  profile_pic: String,
  referenceName: String,
  order_restaurant: String,
  order_people: String,
  order_time: String,
  order_timestamp: Object,
  order_email: String,
  order_phone: String,
  order_contact: []
}, { collection: 'Users' });

module.exports = mongoose.model('Users', usersSchema);

它與生產中使用的相同，但效果很好

Answer 1

試試這個.exec（）返回promise

async function main() {
const users = await schema.find({}).exec();
    console.log(users.length);
    return users;
}

main().then((data) => {
    console.log(data);
}).catch((e) => {
    console.log(e);
});

Answer 2

您可以做到這一點，而您想錯過exec（）

async function main() { const users = await schema.find({}).exec(){ console.log(users.length); }