PHP的MySQL的全局變量

Question

我正在嘗試獲取最后一個訂單ID並將其設置為變量，以便能夠在另一個Order_Items表中設置此ID

$generatedId=0;
    if(isset($_POST['newOrder'])){
        $costumerID = $_POST['CostumerID'];
        $orderDateID =   $_POST['orderDateID'];
        $deliveryDateID =   $_POST['deliveryDateID'];
        $orderRemeraks =   $_POST['orderRemeraks'];
        $orderType =   $_POST['orderType'];

        echo $costumerID;
        $query = "INSERT INTO `orders` (`costumerName`,`dateOfOrder`,`dateOfDelivery`,`remarks`,`type`,`status`)
                VALUES ('$costumerID','$orderDateID','$deliveryDateID','$orderRemeraks','$orderType', 'open');";
        $insertRow = $mysqli->query($query) or die ($mysqli->error.__LINE__);
        $generatedId = $mysqli->insert_id; 
        if($insertRow){
             $GLOBALS['generatedId'] = $mysqli->insert_id; 
            $msg = 'New Order was added ';          
            echo  $msg;
            echo    $generatedId;   
        }

    }

    if(isset($_POST['newItem'])){
        $item_Number = $_POST['item_Number'];
        $itemQty = $_POST['itemQty'];
        $itemKg = $_POST['itemKg'];
        $itemRemarks = $_POST['itemRemarks'];   
        echo   $generatedId;    
        $query = "INSERT INTO `item_number` (`order_id`, `item_number`, `quantity`,`quantity_kg`,`  remarks`,`filling_status`)
                VALUES('$generatedId', '$item_Number','$itemQty','$itemKg','$itemRemarks','not',);";
                $insertRow = $mysqli->query($query) or die ($mysqli->error.__LINE__);

        if($insertRow){ 
            echo  'New Item was added ' ;
        }
    }

問題是$genertedId是0，因為我不能將它放在order_items表中，但是在第一次（在echo $msg ，在打印時，它返回的是真實值；

謝謝

Answer 1

$generatedId = mysqli_insert_id($mysqli); 
if($insertRow){
    $GLOBALS['generatedId'] = $generatedId; 
    $msg = 'New Order was added ';
    echo  $msg;
    echo    $generatedId;   
}