使用隨機運算符將兩個數相加

Question

以下是我的代碼，它可以工作。 它創建兩個隨機數，一個隨機運算符並將它們放在一起，但是這樣做后不求和。 我需要的是程序將其識別為方程式，而不是簡單地打印出各個變量。

因此，避免混淆； 我的問題是：如何使用所選的任何operator將firstNumber和secondNumber求和在一起，而不是簡單地將它們一起打印出來？

from random import choice
from random import randint

ranOperator = ["*", "/", "+", "-"]

def askQuestion():
    firstNumber = randint(1,10)
    secondNumber = randint(1,10)
    operator = choice(ranOperator)

    generateQuestion = ' '.join((str(firstNumber), operator, str(secondNumber)))
    print(generateQuestion)

askQuestion()

當前輸出（示例）：

4 + 3

使用上面相同的數字，我想發生的事情：

7

Answer 1

一種不依賴eval是使用operator模塊來表示操作。

from random import choice
from random import randint
from operator import add, sub, truediv, mul

ranOperator = [add, sub, truediv, mul]

def askQuestion():
    firstNumber = randint(1,10)
    secondNumber = randint(1,10)
    the_operator = choice(ranOperator)

    result = the_operator(firstNumber, secondNumber)
    print(result)

Answer 2

您需要的是eval() 。

eval() 計算所傳遞的字符串作為Python表達式並返回結果。

from random import choice
from random import randint

ranOperator = ["*", "/", "+", "-"]

def askQuestion():
    firstNumber = randint(1,10)
    secondNumber = randint(1,10)
    operator = choice(ranOperator)

    generateQuestion = ' '.join((str(firstNumber), operator, str(secondNumber)))
    print(eval(generateQuestion))

askQuestion()

演示：

>>> eval('1+1')
2
>>> eval('5-3')
2
>>> eval('2*3')
6
>>> eval('6/3')
2

Answer 3

擴展dseuss的答案以合並任何函數，並通過使用字典將函數映射到其符號來打印類似數學的方程式

from random import choice
from random import randint

add = lambda x,y: x+y
substract = lambda x,y: x-y
divide = lambda x,y: x/y
multiply = lambda x,y: x*y

ranOperator = {"*":multiply, "/":divide, "+":add, "-":substract}

def askQuestion():
    firstNumber = randint(1,10)
    secondNumber = randint(1,10)
    operator_key = choice(list(ranOperator.keys()))

    answer = ranOperator[operator_key](firstNumber,secondNumber)
    print("{} {} {} = {}".format(firstNumber, operator_key, secondNumber, answer))

askQuestion()