[英]How to pass multiple parameters not in the URL?
目前,表單數據是通過URL傳遞的,如下所示。
document.getElementById('newChildForm').action = "./populateImageProcessing?personId="+ temp+ "&category="+ strUser+ "&fromDate="+ frmDate+ "&toDate=" + toDate+"&advFromDayID="+advFromDayID+"&advFromMonthID="+advFromMonthID+"&advFromYearID="+advFromYearID+"&advToDayID="+advToDayID+"&advToMonthID="+advToMonthID+"&advToYearID="+advToYearID;
document.getElementById('newChildForm').submit();
我想單獨傳遞表單數據,而不是通過URL。
我用ajax / jQuery嘗試了以下內容
$.ajax({
cache: false,
url : "./populateImageProcessing",
type : "POST",
data : "personId=" + temp + "&category="
+ strUser
+ "&fromDate="+ frmDate+ "&toDate=" + toDate+ "&advFromDayID="+advFromDayID+"&advFromMonthID="+advFromMonthID+"&advFromYearID="+advFromYearID+"&advToDayID="+advToDayID
+"&advToMonthID="+advToMonthID+"&advToYearID="+advToYearID,
success: function(data){
$("#newChildForm").html(data);
}
});
jQuery在SIT環境中工作,但是由於CSP,我在UAT環境中遇到了一些麻煩。
有什么辦法可以使用普通的javascript document.getElementById('newChildForm').action="./populateImageProcessing"
,並分別傳遞參數,而不是在URL中傳遞參數。
請幫忙。 謝謝。
嘗試使用以下代碼:
var data = "personId=" + temp + "&category="+ strUser+ "&fromDate="+ frmDate+ "&toDate=" + toDate+ "&advFromDayID="+advFromDayID+"&advFromMonthID="+advFromMonthID+"&advFromYearID="+advFromYearID+"&advToDayID="+advToDayID+"&advToMonthID="+advToMonthID+"&advToYearID="+advToYearID;
var xhttp= new XMLHttpRequest();
xhttp.open("POST", "populateImageProcessing", true);
xhttp.setRequestHeader("Content-type", "application/x-www-form-urlencoded");
xhttp.onreadystatechange = function() {
if (this.readyState == 4 && this.status == 200) {
document.getElementById('newChildForm').innerHTML = this.responseText
}
};
xhttp.send(data);
你嘗試過這樣的事情嗎?
Json是傳遞多個參數的好方法。
var obj = { personId: temp, category: strUser, fromDate: frmDate, toDate: toDate, advFromDayID :advFromDayID, advFromMonthID: advFromMonthID, advFromYearID: advFromYearID, advToDayID: advToDayID, advToMonthID: advToMonthID, advToYearID: advToYearID };
$.ajax({
cache: false,
url: "./populateImageProcessing",
type: 'POST',
data: JSON.stringify(obj),
contentType: 'application/json; charset=utf-8',
dataType: 'json',
success: function(data){
$("#newChildForm").html(data);
}
});
但是我不知道您是否可以在“服務器”端處理它?
告訴我。 希望能幫助到你。
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