鏈表-迭代添加方法-無getter和setter

Question

您好，我有一個分配是在沒有getter和setter的適當類中創建一個迭代添加方法add（Student s），但是我可能會創建“輔助方法”（不確定其含義）和屬性。

我試圖使方法添加到Group類中：

public void add(Student s) {
    if ( head == null) {
        head = new Student(...); 
        // Struggling because Student constructor requires a String not a Student

    }
}

我可以通過為該名稱創建一個吸氣劑來做到這一點，例如head = new Student（s.getName（））; 但是我不允許使用getter和setter，該怎么辦？ 謝謝

public class Student {

    private final String name;
    private int grade;
    private Student next;

    private static int counter = 0;

    public Student(String name) {
        this.name = name;
        this.grade = 0;
    }

}

public class Group {

    private int groupnumber;
    private Student head;

    // Empty list & group number by default is 2
    public Groupe() {
        this.head = null;
        this.groupnumber = 2;
    }
}

Answer 1

您可以使用副本構造函數。 像新Student(student)一樣。

public class Student {

    private final String name;
    private int grade;
    private Student next;

    private static int counter = 0;

    public Student(Student template) {
        this.name = template.name;
        this.grade = template.grade;
    }

}

或者，也許更簡單：

public void add(Student s) {
    if ( head == null) {
        head = s; 
    }
}