[英]How to change the value of the parameter in python?
注意:沒有修復URL。 意味着不可能總是看到該URL。 我想要適用於所有網址的代碼。
例如, http://januapp.com/demo/search.php?search = aaa
http://januapp.com/demo/search.php?other=aaa
現在我想將其更改為
http://januapp.com/demo/search.php?search=bbb http://januapp.com/demo/search.php?other=bbb
我不知道該怎么辦?
我試過了
import optparse
import requests
import urlparse
parser = optparse.OptionParser()
parser.add_option("-t","--Host", dest="Target", help="Please provide the target", default="true")
options, args = parser.parse_args()
url = options.Target
xss = []
xss.append("bbb")
try:
url2 =urlparse.urlparse(url)
print url2
url3 = urlparse.parse_qs(url2.query)
parametervalue = [key for key, key in url3.iteritems()] #[['aaa']]
parsed = parametervalue.append(xss[0])
print parsed
finalurl = urljoin(url, parsed)
print finalurl
except Exception as e:
print e
所以當我通過這個
xss3.py -t http://januapp.com/demo/search.php?search=aaa
錯誤發生在cmd的下面
ParseResult(scheme='http', netloc='januapp.com', path='/demo/search.php', params='', query='search=aaa', fragment='')
None
name 'urljoin' is not defined
見None
現在就是問題了
我正在使用Python2.7。
非常感謝你。 希望你能解決這個問題。
怎么樣:
ext = "bbb"
a = "http://januapp.com/demo/search.php?search="
print a+ext
ext
是您要搜索的內容, a
是鏈接,然后將它們添加在一起。
或者,您可以像這樣替換值:
ext = "bbb"
a = "http://januapp.com/demo/search.php?search=aaa"
print a.replace('aaa', ext)
使用正則表達式:
import re
ext = "bbb"
a = "http://januapp.com/demo/search.php?search=aaa"
b=re.compile(r".+search=")
print re.search(b,a).group()+ext
您可以嘗試使用這種方法。
url = 'http://januapp.com/demo/search.php?search=aaa'
# First get all your query params
arr = url.split('?')
base_url = arr[0] # This is your base url i.e. 'http://januapp.com/demo/search.php'
params = arr[1] # here are your query params ['search=aaa']
# Now seprate out all the query parameters and their values
arr2 = params.split("=") # This will give you somrthing like this : ['search', 'aaa'], the the value will be next to the key
# This is a dictonary to hold the key value pairs
param_value_dict = {} # {'search': 'aaa'}
for i, str in enumerate(arr2):
if i % 2 == 0:
param_value_dict[str] = arr2[i + 1]
# now if you want to chnage the value of search from 'aaa' to 'bbb', then just change it in the dictonary
param_value_dict['search'] = 'bbb'
# now form the new url from the dictonary
new_url = base_url + '?'
for param_name, param_value in param_value_dict.items():
new_url = new_url + param_name + "=" + param_value + "&"
# remove the extra '&'
new_url = new_url[:len(new_url) - 1]
print(new_url)
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