角路由子惰性模塊

Question

我正在將Angular 4與惰性/共享模塊路由一起使用。

在這里，如何在URL中沒有添加我的惰性模塊名稱的情況下使用路徑？

目前，我的partner組件可通過http://localhost:4200/#/main/partner但我想將其與URL http://localhost:4200/#/partner 。 無需在我的組件后面附加/main 。

對於dashboard ， employeelist和addemployee ，我想直接使用localhost:4200/#/dashboard等訪問。

以下是我的應用程序路由和惰性路由文件。

app.routing.ts

const routes: Routes = [
  { path: '', component: LoginComponent },
  { path: 'emailLogin/forgotpassword', component: ForgotPasswordComponent },
  { path: 'forgotpassword', component: ForgotPasswordComponent },
  { path: 'login', redirectTo: '', component: LoginComponent },
  { path: 'main', loadChildren: './lazy.module#LazyModule' },
  { path: '**', redirectTo: '/main' }
];

export const routing = RouterModule.forRoot(routes, { useHash: true });

lazy.routing.ts

const routes: Routes = [
  { path: 'dashboard', component: DashboardComponent, canActivate: [AuthguardGuardPartnerUser] },
  { path: 'partner', component: PartnerComponent, canActivate: [AuthguardGuard] },
  { path: 'employeelist', component: EmployeeComponent, canActivate: [AuthguardGuardPartnerUser] },
  { path: 'addemployee', component: AddemployeeComponent, canActivate: [AuthguardGuardPartnerUser] },
  { path: 'newsurvey/:neworcopy', component: NewsurveyComponent, canActivate: [AuthguardGuardAdminPartner] },
  // .... Other components
  { path: '404pageNotFound', component: NotfoundComponent },
  { path: '**', redirectTo: '/404pageNotFound' }
];

export const routing: ModuleWithProviders = RouterModule.forChild(routes);

Answer 1

最后我發現只是改變

{ path: '', loadChildren: './lazy.module#LazyModule' },
{ path: '**', redirectTo: '' }

在app.routing.ts解決了我的問題。

Answer 2

我假設您知道您不能讓同一條路線裝載兩種不同的東西，因此您需要進行重組。 我可以想到3種方法。

選項1

const routes: Routes = [
  { path: '', component: LoginComponent },
  { path: 'emailLogin/forgotpassword', component: ForgotPasswordComponent },
  { path: 'forgotpassword', component: ForgotPasswordComponent },
  { path: 'login', redirectTo: '', component: LoginComponent },
  { path: 'partner', loadChildren: './lazy.module#LazyModule' },
  { path: '**', redirectTo: '/main' }
];

export const routing = RouterModule.forRoot(routes, { useHash: true });

const routes: Routes = [
  { path: '', component: PartnerComponent, canActivate: [AuthguardGuard] },
  { path: 'dashboard', component: DashboardComponent, canActivate: [AuthguardGuardPartnerUser] },
  { path: '404pageNotFound', component: NotfoundComponent },
  { path: '**', redirectTo: '/404pageNotFound' }
];

export const routing: ModuleWithProviders = RouterModule.forChild(routes);

這將在/partner處加載延遲模塊，然后由於延遲模塊中的第一條路由現在為”，因此它將加載伙伴組件。 但這顯然意味着您的儀表板現在是/partner/dashboard 。

選項2

或者，將伙伴組件移出惰性模塊並移入您的應用程序模塊：

const routes: Routes = [
  { path: '', component: LoginComponent },
  { path: 'emailLogin/forgotpassword', component: ForgotPasswordComponent },
  { path: 'forgotpassword', component: ForgotPasswordComponent },
  { path: 'login', redirectTo: '', component: LoginComponent },
  { path: 'partner', component: PartnerComponent, canActivate: [AuthguardGuard] },
  { path: 'main', loadChildren: './lazy.module#LazyModule' },
  { path: '**', redirectTo: '/main' }
];

export const routing = RouterModule.forRoot(routes, { useHash: true });

const routes: Routes = [
  { path: 'dashboard', component: DashboardComponent, canActivate: [AuthguardGuardPartnerUser] },
  { path: '404pageNotFound', component: NotfoundComponent },
  { path: '**', redirectTo: '/404pageNotFound' }
];

export const routing: ModuleWithProviders = RouterModule.forChild(routes);

選項3

或者只是將合作伙伴組件移到其自己的模塊中：

const routes: Routes = [
  { path: '', component: LoginComponent },
  { path: 'emailLogin/forgotpassword', component: ForgotPasswordComponent },
  { path: 'forgotpassword', component: ForgotPasswordComponent },
  { path: 'login', redirectTo: '', component: LoginComponent },
  { path: 'main', loadChildren: './lazy.module#LazyModule' },
  { path: 'partner', loadChildren: './partner.module#PartnerModule' },
  { path: '**', redirectTo: '/main' }
];

export const routing = RouterModule.forRoot(routes, { useHash: true });

const routes: Routes = [
  { path: 'dashboard', component: DashboardComponent, canActivate: [AuthguardGuardPartnerUser] },
  { path: '404pageNotFound', component: NotfoundComponent },
  { path: '**', redirectTo: '/404pageNotFound' }
];

export const routing: ModuleWithProviders = RouterModule.forChild(routes);

partner.module.ts

const routes: Routes = [
  { path: '', component: PartnerComponent, canActivate: [AuthguardGuard] },
];

export const routing: ModuleWithProviders = RouterModule.forChild(routes);

我懷疑第三個選項可能最適合，因為它可以使您當前的所有路線保持不變，並且可以提供更大的靈活性。