PHP Regex可以在句子后面沒有單詞時隨時將單詞與單詞匹配

Question

以下是我的句子數組

$strings = [ 
  "I want to match docs with a word New", 
  "But I don't want to match docs with a phrase New York", 
  "However I still want to match docs with a word New which has a phrase New York", 
  "For example let's say there's a New restaraunt in New York and I want this doc to be matched."
] 

我想將上面的句子與單詞new string匹配。 但是當new后面跟着york時，我不想匹配這句話。 我希望能夠在某個小的字距N之內匹配單詞B /后面沒有的單詞A 不是緊挨在“ A”之后。

我如何使用正則表達式獲得預期的結果？

Answer 1

具有負前瞻性的正則表達式應該可以解決問題（請訪問此鏈接以獲取有效的演示）：

.*[Nn]ew(?! [Yy]ork).*

從PHP實現的角度來看，可以如下使用preg_match函數 ：

$strings = [ 
    "I want to match docs with a word New", 
    "But I don't want to match docs with a phrase New York", 
    "However I still want to match docs with a word New which has a phrase New York", 
    "For example let's say there's a New restaraunt in New York and I want this doc to be matched."
];

foreach ($strings as $string) {
    echo preg_match('/.*new(?! york).*/i', $string)."\n";
}

輸出為：

1 -> Match
0 -> Discarded
1 -> Match
1 -> Match

Answer 2

這應該工作：

/(new[^ ?york])|(a[^b])/gi

DEMO