[英]Converting multiple JSON object to one list Mule dataweave
我有如下輸入
{ "ResidentialAddress": { "type": "RES", "Building": "String" }, "Name": "Satheesh", "Status": "Active", "OfficeAddress": { "type": "OFC", "Building": "String" }, "TempAddress": { "type": "TEMP", "Building": "String" } }
我希望將其轉換如下
{Address:[ { "type": "RES", "Building": "String" }, { "type": "OFC", "Building": "String" },{ "type": "TEMP", "Building": "String" } ]}
當我嘗試使用address:payload.ResidentialAddress ++ payload.TempAddress時,它給了我組合的字段,而不是列表,誰能幫忙?
在dataweave中使用扁平化操作。 在dataweave設置有效負載之后。
%dw 1.0
%output application/json
---
(flatten payload) filter ($.type != null)
最終的xml文件將是
<dw:transform-message doc:name="Transform Message">
<dw:set-payload><![CDATA[ %dw 1.0
%output application/json
---
(flatten payload) filter ($.type != null)]]></dw:set-payload>
</dw:transform-message>
<set-payload value="{"Address": #[payload]}" mimeType="application/json" doc:name="Set Payload"/>
<json:object-to-json-transformer doc:name="Object to JSON"/>
這應該適用於過濾具有字符串/整數/布爾值的任何字段:
%dw 1.0
%output application/json
---
{
Address: (flatten payload) filter ($ is :object)
}
針對您的測試數據:
%dw 1.0
%output application/json
---
{ Address:payload filter $ is :object map $}
給出:
{
"Address": [
{
"type": "RES",
"Building": "String"
},
{
"type": "OFC",
"Building": "String"
},
{
"type": "TEMP",
"Building": "String"
}
]
}
但您可能需要調整過濾條件才能使用真實數據...
聲明:本站的技術帖子網頁,遵循CC BY-SA 4.0協議,如果您需要轉載,請注明本站網址或者原文地址。任何問題請咨詢:yoyou2525@163.com.