使用Python和Elementtree解析XML元素

Question

我是python noob，嘗試使用Elementtree解析XML API響應。 響應包含來自表單的自定義數據，我在嘗試訪問某些嵌套元素時遇到了麻煩。 下面是我的代碼：

response = requests.get("https://crm.zoho.com/crm/private/xml/Deals/getCVRecords?newFormat=1&authtoken=authtoken&scope=crmapi&cvName=Open Deals")
tree = ElementTree.fromstring(response.content)
print (response.text)

通過此調用，我可以獲得以下響應：

<?xml version="1.0" encoding="UTF-8" ?>
<response uri="/crm/private/xml/Deals/getCVRecords">
<result>
    <Deals>
        <row no="1">
            <FL val="DEALID">123456789</FL>
            <FL val="SMOWNERID">0000000000</FL>
            <FL val="Deal Owner"><![CDATA[helpme]]></FL>
        </row>
    </Deals>
</result>
</response>

我正在嘗試在[CDATA [helpme]]元素內訪問DEALID＃（123456789）以及HELPME。 任何幫助是極大的贊賞。 謝謝！

Answer 1

我強烈建議您查看https://github.com/martinblech/xmltodict 。 我已經將此用於大量XML處理，並且它非常可靠。

>>> xml = """
... <root xmlns="http://defaultns.com/"
...       xmlns:a="http://a.com/"
...       xmlns:b="http://b.com/">
...   <x>1</x>
...   <a:y>2</a:y>
...   <b:z>3</b:z>
... </root>
... """
>>> xmltodict.parse(xml, process_namespaces=True) == {
...     'http://defaultns.com/:root': {
...         'http://defaultns.com/:x': '1',
...         'http://a.com/:y': '2',
...         'http://b.com/:z': '3',
...     }
... }
True

Answer 2

以下代碼應查找並打印出找到的每個交易ID。

import xml.etree.ElementTree as ET
import requests

root = ET.fromstring(requests.get(your_link).content)

# find 'result' element
result = root.find('result')
# then, find 'Deals' which was nested in 'result'
deals = result.find('Deals')

# this can be simplified:
deals = root.find('result').find('Deals')

for row in deals.findall('row'):  # go through all rows (I assumed there can be more than one)
    deal_id_elem = row.find('FL[@val="DEALID"]')
    print('Found ID', deal_id_elem.text)

deal_id_elem = row.find('FL[@val="DEALID"]')查找屬性val等於DEALID 。 這是Xpath語法的示例用法