[英]How to Decode Nested dictionary with nested arrays using Swift Decodable property?
我需要在swift4中解析的實際JSON是,
{
"class": {
"semester1": [
{
"name": "Kal"
},
{
"name": "Jack"
},
{
"name": "Igor"
}
],
"subjects": [
"English",
"Maths"
]
},
"location": {
"Dept": [
"EnglishDept",
],
"BlockNo": 1000
},
"statusTracker": {
"googleFormsURL": "beacon.datazoom.io",
"totalCount": 3000
}
}
我嘗試過但執行失敗的代碼是
struct Class: Decodable {
let semester: [internalComponents]
let location: [location]
let statusTracker: [statusTracker]
enum CodingKeys: String, CodingKey {
case semester = "semester1"
case location = "location"
case statusTracker = "statusTracker"
}
}
struct location: Decodable {
let Dept: [typesSubIn]
let BlockNo: Int
}
struct statusTracker: Decodable {
let googleFormsURL: URL
let totalCount: Int
}
struct internalComponents: Decodable {
let semester1: [semsIn]
let subjects: [subjectsIn]
}
struct semsIn: Decodable {
let nameIn: String
}
struct subjectsIn: Decodable {
let subjects: String
}
struct Dept: Decodable {
let Depts: String
}
我知道有人可以提供實際格式是完全錯誤的嗎? 我實際上對“主題”的格式感到困惑。它也不是整體編譯的。
有很多問題。
通過部分忽略根對象,您經常犯錯誤。
請看一下JSON:在頂層,有3個鍵class
, location
和statusTracker
。 所有3個鍵的值都是字典,沒有數組。
由於class
(小寫)是保留字,因此我正在使用components
。 順便說一句,請遵循結構名稱以大寫字母開頭的命名約定。
struct Root : Decodable {
let components : Class
let location: Location
let statusTracker: StatusTracker
enum CodingKeys: String, CodingKey { case components = "class", location, statusTracker }
}
還有許多其他問題。 這里是其他結構的合並版本
struct Class: Decodable {
let semester1: [SemsIn]
let subjects : [String]
}
struct Location: Decodable {
let dept : [String]
let blockNo : Int
enum CodingKeys: String, CodingKey { case dept = "Dept", blockNo = "BlockNo" }
}
struct SemsIn: Decodable {
let name: String
}
struct StatusTracker: Decodable {
let googleFormsURL: String // URL is no benefit
let totalCount: Int
}
現在解碼Root
do {
let result = try decoder.decode(Root.self, from: data)
} catch { print(error) }
看起來您以錯誤的方式對Class
對象進行了消毒。 它看起來應該像這樣:
struct Class: Decodable {
let class: [internalComponents]
let location: [location]
let statusTracker: [statusTracker]
}
這里有幾件事引起您的問題。
在我的游樂場嘗試以下代碼:
let jsonData = """
{
"class": {
"semester1": [{
"name": "Kal"
}, {
"name": "Jack"
}, {
"name": "Igor"
}],
"subjects": [
"English",
"Maths"
]
},
"location": {
"Dept": [
"EnglishDept"
],
"BlockNo": 1000
},
"statusTracker": {
"googleFormsURL": "beacon.datazoom.io",
"totalCount": 3000
}
}
""".data(using: .utf8)!
struct Response: Decodable {
let cls: Class
let location: Location
let statusTracker: statusTracker
enum CodingKeys: String, CodingKey {
case cls = "class"
case location
case statusTracker
}
}
struct Class: Decodable {
let semester: [SemesterStudents]
let subjects: [String]
enum CodingKeys: String, CodingKey {
case semester = "semester1"
case subjects
}
}
struct Location: Decodable {
let dept: [String]
let blockNo: Int
enum CodingKeys: String, CodingKey {
case dept = "Dept"
case blockNo = "BlockNo"
}
}
struct statusTracker: Decodable {
let googleFormsURL: URL
let totalCount: Int
}
struct SemesterStudents: Decodable {
let name: String
}
struct Dept: Decodable {
let Depts: String
}
do {
let result = try JSONDecoder().decode(Response.self, from: jsonData)
print(result)
} catch let error {
print(error)
}
另一種方法是創建一個與JSON緊密匹配的中間模型,讓Swift生成對它進行解碼的方法,然后從最終數據模型中挑選出所需的片段:
// snake_case to match the JSON
fileprivate struct RawServerResponse: Decodable {
struct User: Decodable {
var user_name: String
var real_info: UserRealInfo
}
struct UserRealInfo: Decodable {
var full_name: String
}
struct Review: Decodable {
var count: Int
}
var id: Int
var user: User
var reviews_count: [Review]
}
struct ServerResponse: Decodable {
var id: String
var username: String
var fullName: String
var reviewCount: Int
init(from decoder: Decoder) throws {
let rawResponse = try RawServerResponse(from: decoder)
// Now you can pick items that are important to your data model,
// conveniently decoded into a Swift structure
id = String(rawResponse.id)
username = rawResponse.user.user_name
fullName = rawResponse.user.real_info.full_name
reviewCount = rawResponse.reviews_count.first!.count
}
}
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