Javascript將當前時間轉換為timeago

Question

我一直在嘗試將當前時間轉換為timeago，例如facebook和twitter（2分鍾前，30秒前）。 為此，我正在考慮當前時間，並借助將其轉換為大約時間的功能。 代碼如下：

 var current = new Date(); console.log(timeDifference(current, new Date(2018, 03, 27, 10, 30, 00, 00))); console.log(timeDifference(current, new Date(2018, 03, 27, 10, 00, 00, 00))); function timeDifference(current, previous) { var msPerMinute = 60 * 1000; var msPerHour = msPerMinute * 60; var msPerDay = msPerHour * 24; var msPerMonth = msPerDay * 30; var msPerYear = msPerDay * 365; var elapsed = current - previous; if (elapsed < msPerMinute) { return Math.round(elapsed / 1000) + ' seconds ago'; } else if (elapsed < msPerHour) { return Math.round(elapsed / msPerMinute) + ' minutes ago'; } else if (elapsed < msPerDay) { return Math.round(elapsed / msPerHour) + ' hours ago'; } else if (elapsed < msPerMonth) { return 'approximately ' + Math.round(elapsed / msPerDay) + ' days ago'; } else if (elapsed < msPerYear) { return 'approximately ' + Math.round(elapsed / msPerMonth) + ' months ago'; } else { return 'approximately ' + Math.round(elapsed / msPerYear) + ' years ago'; } } 

但是，它無法正常工作，我似乎不知道為什么？

Answer 1

您的月份減少一（以0為基數）。 （當然，根據時區可能仍會返回錯誤結果。）

 var current = new Date(); console.log(timeDifference(current, new Date(2018, 02, 27, 10, 30, 00, 00))); console.log(timeDifference(current, new Date(2018, 02, 27, 10, 00, 00, 00))); function timeDifference(current, previous) { var msPerMinute = 60 * 1000; var msPerHour = msPerMinute * 60; var msPerDay = msPerHour * 24; var msPerMonth = msPerDay * 30; var msPerYear = msPerDay * 365; var elapsed = current - previous; if (elapsed < msPerMinute) { return Math.round(elapsed / 1000) + ' seconds ago'; } else if (elapsed < msPerHour) { return Math.round(elapsed / msPerMinute) + ' minutes ago'; } else if (elapsed < msPerDay) { return Math.round(elapsed / msPerHour) + ' hours ago'; } else if (elapsed < msPerMonth) { return 'approximately ' + Math.round(elapsed / msPerDay) + ' days ago'; } else if (elapsed < msPerYear) { return 'approximately ' + Math.round(elapsed / msPerMonth) + ' months ago'; } else { return 'approximately ' + Math.round(elapsed / msPerYear) + ' years ago'; } } 

Answer 2

問題出在您的測試中，因為月份從0開始。

console.log(timeDifference(current, new Date(2018, 03, 27, 10, 30, 00, 00)));
console.log(timeDifference(current, new Date(2018, 03, 27, 10, 00, 00, 00)));

至

console.log(timeDifference(current, new Date(2018, 02, 27, 10, 30, 00, 00)));
console.log(timeDifference(current, new Date(2018, 02, 27, 10, 00, 00, 00)));

並且您的代碼可以正常工作。