比較上一行SQL中的值

Question

假設您在sqllite有一些像這樣的表

c.execute('''CREATE TABLE customers
         (customer_id INT, name VARCHAR)''')

c.execute('''CREATE TABLE orders
         (order_id INT, quantity INT, order_date DATETIME, customer_id INT)''')

您如何比較兩個不同日期之間的客戶訂單數量？

我已經查詢到了我每天都有客戶計數的地方

SELECT A.customer_id, name, SUM(quantity), strftime('%Y-%m-%d', order_date) d FROM orders " \
            "A LEFT JOIN customers B on A.customer_id = B.customer_id "\
            "GROUP BY d, A.customer_id " \
            "ORDER BY B.name LIMIT 20;

這樣給我一些結果

(0, 'customer_0', 423, '2018-03-27')
(0, 'customer_0', 1054, '2018-03-28')
(1, 'customer_1', 757, '2018-03-21')
(1, 'customer_1', 314, '2018-03-22')

我需要能夠將一行與上一行進行比較，並得到這樣的差異-

customer_0, 631
customer_1, -443

Answer 1

SELECT
  C.customer_id,
  C.name,
  SUM(CASE WHEN strftime('%Y-%m-%d', O.order_date) = S.final_order_date THEN O.quantity END)
  -
  SUM(CASE WHEN strftime('%Y-%m-%d', O.order_date) = S.first_order_date THEN O.quantity END)
      AS delta_value
FROM
  customers    C
INNER JOIN
(
  SELECT
    customer_id,
    strftime('%Y-%m-%d', MIN(order_date))   first_order_date,
    strftime('%Y-%m-%d', MAX(order_date))   final_order_date
  FROM
    orders
  GROUP BY
    customer_id 
)
  S
    ON S.customer_id = C.customer_id
INNER JOIN
  orders    O
    ON O.customer_id = C.customer_id
GROUP BY
  C.customer_id,
  C.name
ORDER BY
  C.name
LIMIT
  20