[英]why i can't access to method from another class
我正在嘗試從Firebase
獲取問題並將其顯示在TextView
。 首先,我有GameManager
類,在這個class
我得到了所有問題並將它們添加到ArrayList
:
public class GameManager {
Context context;
ArrayList<MyQuestion> listquestions = new ArrayList<>();
private MyQuestion[] questions;
private String[][] options;
private int[] answers;
private DatabaseReference mDatabase;
public GameManager(Context context) {
getQuestions();
/*new String[]{"In which country were the first Olympic Games held?", "Which popular american TV show holds the record for most viewers for a finale?", "Where did Chess originate from?", "Which version of Android did not support phones?"};*/
options = new String[][]{{"Greece", "Spain", "USA", "Russia"},
{"Cheers", "Friends", "M*A*S*H", "Seinfeld"},
{"China", "India", "UK", "Germany"},
{"Donut", "Eclair", "Gingerbread", "Honeycomb"}};
// 1 - first option, 4 - fourth option
answers = new int[]{1, 3, 2, 4};
this.context = context;
listquestions = new ArrayList<>();
}
public QuestionModel generateRandomQuestion(long previousId) {
Random random = new Random();
int index = random.nextInt(questions.length);
while (index == previousId) {
index = random.nextInt(questions.length);
}
QuestionModel testQuestion = new QuestionModel();
testQuestion.setId(index);
testQuestion.setQuestion(questions[index].getQuestion());
List<OptionModel> options = new ArrayList<OptionModel>();
OptionModel option1 = new OptionModel();
option1.setOptionId(1);
option1.setOptionString(this.options[index][0]);
option1.setCorrectAnswer(answers[index] == 1);
OptionModel option2 = new OptionModel();
option2.setOptionId(2);
option2.setOptionString(this.options[index][1]);
option2.setCorrectAnswer(answers[index] == 2);
....
options.add(option1);
options.add(option2);
.....
testQuestion.setOptions(options);
return testQuestion;
}
public void getQuestions() {
mDatabase = FirebaseDatabase.getInstance().getReference();
final DatabaseReference mUser = mDatabase.child("Quizy").child("ChallengeQuestions").child("Questions");
mUser.addListenerForSingleValueEvent(new ValueEventListener() {
@Override
public void onDataChange(DataSnapshot dataSnapshot) {
for (DataSnapshot postSnapshot : dataSnapshot.getChildren()) {
MyQuestion user = postSnapshot.getValue(MyQuestion.class);
assert user != null;
listquestions.add(user);
}
questions = listquestions.toArray(new MyQuestion[listquestions.size()]);
}
@Override
public void onCancelled(DatabaseError databaseError) {
}
});
}
}
public void generateNewQuestion() {
long previousQuestionId = -1;
try {
previousQuestionId = mGameModel.getQuestion().getId();
} catch (NullPointerException e) {
previousQuestionId = -1;
}
GameManager gameManager = new GameManager(getApplicationContext());
mGameModel.setQuestion(gameManager.generateRandomQuestion(previousQuestionId));
mGameModel.getGameMaster().setDidPlayerAnswer(false);
mGameModel.getGameMaster().setPlayerAnswerCorrect(false);
mGameModel.getGameSlave().setDidPlayerAnswer(false);
mGameModel.getGameSlave().setPlayerAnswerCorrect(false);
}
我的問題是我無法使用此方法generateRandomQuestion 。 如果我想動態獲取問題(使用Firebase
),則無法訪問它,但是當我以static
方式設置問題時,我不知道為什么。
如果您嘗試從另一個類調用此方法,則該方法將無效,因為您將該方法設為private
這意味着只能在該類本身內對其進行訪問。 您不能從另一個類調用此方法。
如果此方法不需要private
考慮將其更改為public
或protected
這也可能會有所幫助: 公共,私有和受保護的區別是什么?
聲明:本站的技術帖子網頁,遵循CC BY-SA 4.0協議,如果您需要轉載,請注明本站網址或者原文地址。任何問題請咨詢:yoyou2525@163.com.