如何用jargo忽略其他參數？

Question

我試圖讓jargo忽略任何數量的“在這里垃圾”字符串。 我怎樣才能做到這一點？ 這是我想出的代碼：

@Test
public void testUsage() throws Exception
{
    Argument<Integer> nrOfPotatoes = Arguments.integerArgument("-n").build();
    ParsedArguments parsedArguments = CommandLineParser.withArguments(nrOfPotatoes).parse("-n", "123", "junk-be-here");
    int potatoesToPlant = parsedArguments.get(nrOfPotatoes);
    System.out.println("Hold on, planting " + potatoesToPlant + " potatoes");
}

但是我得到：

se.softhouse.jargo.ArgumentExceptions$UnexpectedArgumentException: Unexpected argument: junk-be-here, previous argument: 123
at se.softhouse.jargo.ArgumentExceptions.forUnexpectedArgument(ArgumentExceptions.java:299)
at se.softhouse.jargo.CommandLineParserInstance.getDefinitionForCurrentArgument(CommandLineParserInstance.java:329)
at se.softhouse.jargo.CommandLineParserInstance.parseArguments(CommandLineParserInstance.java:262)
at se.softhouse.jargo.CommandLineParserInstance.parse(CommandLineParserInstance.java:234)
at se.softhouse.jargo.CommandLineParserInstance.parse(CommandLineParserInstance.java:228)
at se.softhouse.jargo.CommandLineParser.parse(CommandLineParser.java:224)
at

.....

Answer 1

您可以使用帶索引的參數（通過不為參數指定名稱），並設置variableArity （允許任意數量的參數）。

    @Test
public void testUsage() throws Exception
{
    Argument<List<String>> junk = Arguments.stringArgument().variableArity().build();
    Argument<Integer> nrOfPotatoes = Arguments.integerArgument("-n").build();
    ParsedArguments parsedArguments = CommandLineParser.withArguments(junk, nrOfPotatoes).parse("-n", "123", "junk-be-here");
    int potatoesToPlant = parsedArguments.get(nrOfPotatoes);
    System.out.println("Hold on, planting " + potatoesToPlant + " potatoes");
    System.out.println("Junk:" + parsedArguments.get(junk));
}

打印：

Hold on, planting 123 potatoes
Junk:[junk-be-here]