[英]I'm trying to plot proportions instead of what I have in ggplot2 in R but I am unsure how to go about doing so
[英]I'm trying to recreate a specific plot in R (ggplot2)
盡管已嘗試過多種類型的線,但我無法得到相同的結果。 以下是我需要線條的方式:
這就是我到目前為止得到它的方式(我堅持):
這是我的代碼:
myData <- read.csv(file.choose(), header = TRUE)
require(ggplot2)
g <- ggplot(myData, aes(speed, resp))
g + geom_point(aes(color = padlen, shape = padlen)) +
geom_smooth(method = "lm", formula = y ~ splines::bs(x, df = 4, degree = 2), se = FALSE, aes(color = padlen), linetype = "solid", size = 1) +
scale_color_manual(values = c("red", "black")) +
scale_shape_manual(values = c(2, 1))
這是數據庫(dput):
myData <- structure(list(resp = c(0, 0.125, 0.583333333, 1, 0.958333333,
1, 0, 0.041666667, 0.25, 0.916666667, 1, 1), padlen = structure(c(2L,
2L, 2L, 2L, 2L, 2L, 1L, 1L, 1L, 1L, 1L, 1L), .Label = c("big",
"small"), class = "factor"), speed = c(2L, 3L, 4L, 5L, 6L, 7L,
2L, 3L, 4L, 5L, 6L, 7L)), .Names = c("resp", "padlen", "speed"
), class = "data.frame", row.names = c(NA, -12L))
我也嘗試了所有這些多項式模型(和其他),但沒有一個工作:
## Quadratic model
lmQuadratic <- lm(formula = y ~ x + I(x^2),
data = fpeg)
## Cubit model
lmCubic <- lm(formula = y ~ x + I(x^2) + I(x^3),
data = fpeg)
## Fractional polynomial model
lmFractional <- lm(formula = y ~ x + I(x^2) + I(x^(1/2)),
data = fpeg)
那么,我應該做什么/不做什么來讓我的線條與原來的線條相同? 謝謝。
而不是在geom_smooth
中使用method = "lm"
而是使用帶有二項式族的glm
。 glm
-smooth只給出0到1之間的值(你想要的是什么,因為你正在處理比例)。
library(ggplot2)
ggplot(myData, aes(speed, resp)) +
geom_point(aes(color = padlen, shape = padlen)) +
geom_smooth(method = "glm", method.args = list(family = "binomial"),
se = FALSE, aes(color = padlen), linetype = "solid", size = 1) +
scale_color_manual(values = c("red", "black")) +
scale_shape_manual(values = c(2, 1)) +
theme_classic()
數據
myData <-
structure(list(resp = c(0, 0.125, 0.583333333, 1, 0.958333333, 1, 0,
0.041666667, 0.25, 0.916666667, 1, 1),
padlen = c("small", "small", "small", "small", "small",
"small", "big", "big", "big", "big", "big", "big"),
speed = c(2L, 3L, 4L, 5L, 6L, 7L, 2L, 3L, 4L, 5L, 6L, 7L)),
.Names = c("resp", "padlen", "speed"), class = "data.frame",
row.names = c(NA, -12L))
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