嘗試在Java中實現MD5哈希的簡單實現

Question

為了練習，我正在嘗試實現在Java上的Wikipedia上找到的MD5哈希算法。

我將我的實現結果與JDK實現返回的結果進行比較。 我不是想弄清楚最好，最優雅，最有效的實現方式。 只有一個有效。

似乎我的實現只產生了一半的正確結果，我無法理解為什么。

public static String md5DigestHexString(String message) {

    int[] s = { 7, 12, 17, 22, 7, 12, 17, 22, 7, 12, 17, 22, 7, 12, 17, 22, 5, 9, 14, 20, 5, 9, 14, 20, 5, 9, 14,
            20, 5, 9, 14, 20, 4, 11, 16, 23, 4, 11, 16, 23, 4, 11, 16, 23, 4, 11, 16, 23, 6, 10, 15, 21, 6, 10, 15,
            21, 6, 10, 15, 21, 6, 10, 15, 21 };

    int[] K = { 0xd76aa478, 0xe8c7b756, 0x242070db, 0xc1bdceee, 0xf57c0faf, 0x4787c62a, 0xa8304613, 0xfd469501,
            0x698098d8, 0x8b44f7af, 0xffff5bb1, 0x895cd7be, 0x6b901122, 0xfd987193, 0xa679438e, 0x49b40821,
            0xf61e2562, 0xc040b340, 0x265e5a51, 0xe9b6c7aa, 0xd62f105d, 0x02441453, 0xd8a1e681, 0xe7d3fbc8,
            0x21e1cde6, 0xc33707d6, 0xf4d50d87, 0x455a14ed, 0xa9e3e905, 0xfcefa3f8, 0x676f02d9, 0x8d2a4c8a,
            0xfffa3942, 0x8771f681, 0x6d9d6122, 0xfde5380c, 0xa4beea44, 0x4bdecfa9, 0xf6bb4b60, 0xbebfbc70,
            0x289b7ec6, 0xeaa127fa, 0xd4ef3085, 0x04881d05, 0xd9d4d039, 0xe6db99e5, 0x1fa27cf8, 0xc4ac5665,
            0xf4292244, 0x432aff97, 0xab9423a7, 0xfc93a039, 0x655b59c3, 0x8f0ccc92, 0xffeff47d, 0x85845dd1,
            0x6fa87e4f, 0xfe2ce6e0, 0xa3014314, 0x4e0811a1, 0xf7537e82, 0xbd3af235, 0x2ad7d2bb, 0xeb86d391 };

    int a0 = 0x67452301; // A
    int b0 = 0xefcdab89; // B
    int c0 = 0x98badcfe; // C
    int d0 = 0x10325476; // D


    byte[] msgInBytes = message.getBytes();

    int tempMsgTotalNbOfBytes = msgInBytes.length + 1 + 8;
    int modOfMsgInBytes = tempMsgTotalNbOfBytes % 64;

    int nbOfZeroBytesNeeded = 0;
    if (modOfMsgInBytes > 0)
        nbOfZeroBytesNeeded = 64 - modOfMsgInBytes;

    tempMsgTotalNbOfBytes += nbOfZeroBytesNeeded;

    byte[] finalTabForMsgInBytesToDigest = Arrays.copyOf(msgInBytes, tempMsgTotalNbOfBytes);

    finalTabForMsgInBytesToDigest[msgInBytes.length] = (byte) 128;

    long msgLengthInBits = (long) msgInBytes.length * 8;
    for (int i = 0; i < 8; i++) {

        finalTabForMsgInBytesToDigest[tempMsgTotalNbOfBytes - 8 + i] = (byte) msgLengthInBits;

        msgLengthInBits >>>= 8;
    }

    for (int i = 0; i < finalTabForMsgInBytesToDigest.length; i += 64) {
        int A = a0;
        int B = b0;
        int C = c0;
        int D = d0;
        int F = 0, g = 0;

        for (int j = 0; j < 64; j++) {
            if (0 <= j && j <= 15) {
                F = (B & C) | ((~B) & D);
                g = j;
            } else if (16 <= j & j <= 31) {
                F = (D & B) | ((~D) & C);
                g = (5 * j + 1) % 16;
            } else if (32 <= j && j <= 47) {
                F = B ^ C ^ D;
                g = (3 * j + 5) % 16;
            } else if (48 <= j && j <= 63) {
                F = C ^ (B | (~D));
                g = (7 * j) % 16;
            }
            int chunk = finalTabForMsgInBytesToDigest[i + g * 4 + 3] << 24;
            chunk |= finalTabForMsgInBytesToDigest[i + g * 4 + 2] << 16;
            chunk |= finalTabForMsgInBytesToDigest[i + g * 4 + 1] << 8;
            chunk |= finalTabForMsgInBytesToDigest[i + g * 4];

            F = F + A + K[j] + chunk;
            A = D;
            D = C;
            C = B;
            B = B + Integer.rotateLeft(F, s[j]);
        }

        a0 = a0 + A;
        b0 = b0 + B;
        c0 = c0 + C;
        d0 = d0 + D;
    }
    byte[] md5 = new byte[16];
    int count = 0;
    for (int k = 0; k < 4; k++) {
        int n = (k == 0) ? a0 : ((k == 1) ? b0 : ((k == 2) ? c0 : d0));
        for (int j = 0; j < 4; j++) {
            md5[count] = (byte) n;
            count++;
            n >>>= 8;
        }
    }

    StringBuilder sb = new StringBuilder();
    for (int l = 0; l < md5.length; l++) {
        sb.append(String.format("%02X", md5[l] & 0xFF));
    }
    return sb.toString().toLowerCase();
}

以下是一些測試結果：

Message : bca
my MD5 : b64eab8ce39e013604e243089c687e4f
JV MD5 : b64eab8ce39e013604e243089c687e4f

Message : helmo
my MD5 : 307efe36da7042dbbb254ba88ccb38a3
JV MD5 : 40eb7df9494c88d9f0302dea74c6c327

Message : hello world
my MD5 : 5eb63bbbe01eeed093cb22bb8f5acdc3
JV MD5 : 5eb63bbbe01eeed093cb22bb8f5acdc3

Message : The quick brown fox jumps over the lazy dog
my MD5 : 9e107d9d372bb6826bd81d3542a419d6
JV MD5 : 9e107d9d372bb6826bd81d3542a419d6

Message : 11111111112222222222333333333344444444445555555555666666666677777777778888888888999999999900000000001111111111222222222233333333334444444444555555555566666666667777777777888888888899999999990000000000
my MD5 : 61b7deb6c10abea9e621a228073473e9
JV MD5 : 6290364f4986f468e351f14e38c8a737

編輯：這是測試代碼......

公共課Md5Hash {

public static void main(String[] args) {
     String[] messages = { "", "bca", "helmo", "hello world", "The quick brown fox jumps over the lazy dog", "11111111112222222222333333333344444444445555555555666666666677777777778888888888999999999900000000001111111111222222222233333333334444444444555555555566666666667777777777888888888899999999990000000000"
     };

    for (String message : messages) {
        System.out.println("Message : " + message);
        System.out.println("my MD5 : " + md5DigestHexString(message));
        System.out.println("JV MD5 : " + md5DigestJavaHexString(message));
        System.out.println();
    }
}

以下是使用JDK實現的代碼：

public static String md5DigestJavaHexString(String message) {
    StringBuffer sb = new StringBuffer();
    MessageDigest md;
    try {
        md = MessageDigest.getInstance("MD5");
        md.update(message.getBytes());
        byte[] digest = md.digest();
        for (byte b : digest) {
            sb.append(String.format("%02x", b & 0xff));
        }
    } catch (NoSuchAlgorithmException e) {
        e.printStackTrace();
    }
    return sb.toString();
}

Answer 1

使用IDE，您將看到以下條件不正確：

if (0 <= j && j <= 15) {

} else if (16 <= j & j <= 31) {

} else if (32 <= j && j <= 47) {

} else if (48 <= j && j <= 63) {

}

第一個條件0 <= j 始終為真 。 將條件更改為以下內容有助於解決您的問題：

if (j <= 15) {

} else if (j <= 31) {

} else if (j <= 47) {

} else if (j <= 63) {

}

其次，下面的代碼沒有得到塊的正確值（它應該是小端）：

int chunk = finalTabForMsgInBytesToDigest[i + g * 4 + 3] << 24;
chunk |= finalTabForMsgInBytesToDigest[i + g * 4 + 2] << 16;
chunk |= finalTabForMsgInBytesToDigest[i + g * 4 + 1] << 8;
chunk |= finalTabForMsgInBytesToDigest[i + g * 4];

您可以使用以下代碼（ 在第一個循環內 ）：

IntBuffer intBuf = ByteBuffer.wrap(finalTabForMsgInBytesToDigest).order(ByteOrder.LITTLE_ENDIAN).asIntBuffer();
int[] array = new int[16];  // We're storing 16 integers each iteration.
intBuf.get(new int[i / 4]); // Skip integers that we've already used.
intBuf.get(array);          // Get the next 16 integers.
int chunk = array[g];       // Save the chunk.

完成這些更改后，所有測試用例都會通過！