驗證imagefile是否為空還對不為空的文件進行單獨的查詢

Question

我想有一個單獨的查詢，當圖像文件保留為空白時，僅更新圖像名稱和圖像文本；當用戶選擇新圖像時，更新所有圖像名稱，圖像文本和圖像本身。這是我的查詢：

if (isset($_POST['update'])) {

    $update_id = $_POST["id"];
    $update_imagename = $_POST['imagename'];

    // Get image name
    $update_imagefile = $_FILES['imagefile']['name'];

    // Get text
    $update_imagetext = mysqli_real_escape_string($db, $_POST['imagetext']);

    // image file directory
    $target = "images/portfolio/" . basename($update_imagefile);

    $update_query = "UPDATE `images` SET `imagename`='$update_imagename',`imagetext`='$update_imagetext',`imagefile`= '$update_imagefile'  WHERE `imageid`='$update_id'"; //delete query  
    $run = mysqli_query($db, $update_query);

    if ($run) {
        //javascript function to open in the same window   
        echo "<script>window.open('artworksupdate.php?=image has been updated','_self')</script>";
    }

Answer 1

要確定您是否具有uploadFile，請在執行示例后執行!empty($_POST['imagefile']) 。

if (!empty($_POST)) {

    $update_id = $_POST["id"];
    // Get image name
    $update_imagename = $_POST['imagename'];
    // Get image description
    $update_imagetext = $_POST['imagetext'];
    // Determine if we have input file set
    $haveUploadedFile = !empty($_POST['imagefile']);
    if( $haveUploadedFile ) {
        // [...] do your upload stuff here.
        $update_imagefile = 'myAwesomeImage.png';
        $update_query = "UPDATE `images` SET `imagename`='$update_imagename',`imagetext`='$update_imagetext',`imagefile`= '$update_imagefile'  WHERE `imageid`='$update_id'"; //delete query
    }
    else {
        $update_query = "UPDATE `images` SET `imagename`='$update_imagename',`imagetext`='$update_imagetext' WHERE `imageid`='$update_id'"; //delete query
    }
    $run = mysqli_query($db, $update_query);
    //[...]

}