Python的紙漿不匹配變量dict值

Question

我正在努力簡化約束幾天。 還在學習python。 請幫助並提前感謝您。

    Employees=['Paul', 'Ben', 'Nasim', 'Ceci', 'Victoria',]
    Days = ['Monday', 'Tuesday', 'Wednesday', 'Thursday', 'Friday',      
    'Saturday', 'Sunday']

    avail = pulp.LpVariable.dicts("on_off", ((employee, day) for     
    employee in Employees for day in Days), cat="Binary")

    requests={"Paul": {"Monday":1, "Tuesday":1, "Wednesday":1,   
    "Thursday":1, "Friday":1, "Saturday":1, "Sunday":1},
    "Ben": {"Monday":1, "Tuesday":1, "Wednesday":1, "Thursday":1, 
    "Friday":1, "Saturday":1, "Sunday":0},
    "Nasim": {"Monday":1, "Tuesday":1, "Wednesday":1, "Thursday":1, 
    "Friday":1, "Saturday":1, "Sunday":1},
    "Ceci": {"Monday":1, "Tuesday":1, "Wednesday":1, "Thursday":1, 
    "Friday":1,"Saturday":1, "Sunday":0},
    "Victoria": {"Monday":1, "Tuesday":1, "Wednesday":0, "Thursday":0, 
    "Friday":0, "Saturday":0, "Sunday":0}}



    for employee, day in avail:
            prob += avail[employee, day] == [requests[i][j] for i in    
            requests for j in requests[i]]

例如，前幾個約束：

"_C13: on_off_('Paul',_'Monday') = 28
_C14: on_off_('Paul',_'Tuesday') = 28
_C15: on_off_('Paul',_'Wednesday') = 28
_C16: on_off_('Paul',_'Thursday') = 28
_C17: on_off_('Paul',_'Friday') = 28
_C18: on_off_('Paul',_'Saturday') = 28" 

（在我的嵌套字典中，“ 28”恰好是所有1和0的總和。）

相反，我喜歡讓嵌套字典中的每個變量都匹配1和0。

"_C13: on_off_('Paul',_'Monday') = 1
_C14: on_off_('Paul',_'Tuesday') = 1
_C15: on_off_('Paul',_'Wednesday') = 1
_C16: on_off_('Paul',_'Thursday') = 1
_C17: on_off_('Paul',_'Friday') = 1
_C18: on_off_('Paul',_'Saturday') = 1"

Answer 1

在==符號后，您希望字典中的值為1或0，因此應使用：

for employee, day in avail:
    prob += avail[employee, day] == requests[employee][day]

通過請求[員工]，您可以為該員工選擇詞典

requests['Paul'] = {"Monday":1, "Tuesday":1, "Wednesday":1,   
"Thursday":1, "Friday":1, "Saturday":1, "Sunday":1}

然后通過添加[day]從該詞典中選擇日期：

 requests['Paul']['Monday'] = 1