Foreach陣列錯誤（PHP）

Question

我想創建一個循環菜單為1對象菜單的動態菜單。 但是發生了錯誤。 我們的代碼在下面：

$menus = [{"id" => 1, "label" => "content", "parent_id" => 0},{"id" => 2, "label" => "inbox", "id" => 3, "parent_id" => 0}, {"id" => 4, "label" => "item", "parent_id" => 0}];
$sub_menus = [{"id" => 5, "label" => "banner", "parent_id" => 1},{"id" => 6, "label" => "ads", "parent_id" => 1}];

foreach($menus as $row => $value){
    $nav[$row] = $value;
    foreach($sub_menus as $r => $v) {
        if($v['parent_id'] == $value['id']){
            $nav[$row]['sub_menu'][$r] = $v;
        }
     }
 }

我收到錯誤通知，“ 對App \\ Menu重載元素的間接修改無效 ”

請幫我 ：）

Answer 1

該代碼正在運行。 您的陣列中有很多錯誤。

固定的 ：

$menus = [
            [
                "id" => 1,
                "label" => "content",
                "parent_id" => 0
            ],
            [
                "id" => 2,
                "label" => "inbox",
                "parent_id" => 0
            ],
            [
                "id" => 4,
                "label" => "item",
                "parent_id" => 0
            ]
        ];

        $sub_menus = [
            [
                "id" => 5,
                "label" => "banner",
                "parent_id" => 1
            ],
            [
                "id" => 6,
                "label" => "ads",
                "parent_id" => 1
            ]
        ];

        foreach($menus as $row => $value){
            $nav[$row] = $value;
            foreach($sub_menus as $r => $v) {
                if($v['parent_id'] == $value['id']){
                    $nav[$row]['sub_menu'][$r] = $v;
                }
            }
        }

Answer 2

您有一個損壞的數組，類似於將json不正確地轉換為數組；

您可以在此處測試（執行）（工作示例）