獨特與內在的結合

Question

誰能告訴我用此序列查詢與Sequelize取得相同結果的最佳方法是什么：

SELECT DISTINCT (c.id),
    c.*
FROM table1 a
INNER JOIN table2 b
    ON b.id = a."table2Id" 
INNER JOIN table3 c
    ON c.id = b."table3Id"
ORDER BY c.date DESC
LIMIT 10;

現在，“ include”幾乎提供了我進行內部聯接所需的結果，但是聯接表上的“ distinct”看起來很難獲得...

目標是聯接3個表，在第三個聯接的日期之前對它們進行排序，避免多次從第三個聯接獲得相同的條目，最后只從第三個聯接獲得唯一的條目（它將始終具有“ table1”關系）因為我們從此表開始獲取它們）。

Answer 1

SELECT DISTINCT (b.table3Id), c.*
FROM table1 a
INNER JOIN table2 b ON b.id = a."table2Id" 
INNER JOIN table3 c ON c.id = b."table3Id"
ORDER BY c.date DESC
LIMIT 10;

Answer 2

Table1.findAll({ 
    attributes: [ [sequelize.fn('DISTINCT', sequelize.col('table1.table3Id')), 'c.id'] ],
    include: [ [Table2, "b"], [Table3, "c" ] ],
    order: [ [Table1.associations.Table3, 'date', 'DESC'] ],
    limit: 10
})