我無法從Firebase獲取值並將它們放在片段中的TextView中

Question

在我的應用程序中，我創建了登錄和注冊頁面，並將用戶名和電子郵件保存到我的Firebase數據庫中。 我還用片段進行了底部導航。 我想從Firebase中獲取這些值（名稱，郵件），並將其放入配置文件片段的TextView中。 當我嘗試此操作時，我的應用程序崩潰了。 我怎么解決這個問題？

public class ProfileFragment extends Fragment {
    private FirebaseDatabase mFirebaseDatabase;
    private FirebaseAuth mAuth;
    private String userID;

    private TextView tName;
    private TextView tEmail;


    public View onCreateView(LayoutInflater inflater, @Nullable ViewGroup container, @Nullable Bundle savedInstanceState) {

        View profileView = inflater.inflate(R.layout.fragment_profile, null);

        tName=profileView.findViewById(R.id.tv_name);
        tEmail=profileView.findViewById(R.id.tv_email);


        mAuth=FirebaseAuth.getInstance();
        mFirebaseDatabase=FirebaseDatabase.getInstance();
        final DatabaseReference myRef=mFirebaseDatabase.getReference("users");
        FirebaseUser user=mAuth.getCurrentUser();
        userID=user.getUid();

        myRef.addValueEventListener(new ValueEventListener() {
            @Override
            public void onDataChange(DataSnapshot dataSnapshot) {
                for(DataSnapshot ds: dataSnapshot.getChildren()){
                    User user=new User();
                    user.setUserName(ds.child(userID).getValue(User.class).getUserName());
                    user.setUserEmail(ds.child(userID).getValue(User.class).getUserEmail());

                    tName.setText(user.getUserName());
                    tEmail.setText(user.getUserEmail());
                }
            }

            @Override
            public void onCancelled(DatabaseError databaseError) {}
        });

        return profileView;
    }
}

Answer 1

在xml文件夾中創建文件

<?xml version="1.0" encoding="utf-8"?>
<defaultsMap>
    <entry>
       <key>email</key>
       <value>name</value>
</entry>

public FirebaseRemoteConfig getmFirebaseRemoteConfig() {

    mFirebaseRemoteConfig = FirebaseRemoteConfig.getInstance();

    FirebaseRemoteConfigSettings configSettings = new FirebaseRemoteConfigSettings.Builder()
             //.setDeveloperModeEnabled(BuildConfig.DEBUG)
            .setDeveloperModeEnabled(false)
            .build();
    mFirebaseRemoteConfig.setConfigSettings(configSettings);

    mFirebaseRemoteConfig.setDefaults(R.xml.remote_config_defaults);


    return mFirebaseRemoteConfig;
}

Answer 2

假設您的數據庫結構與此類似：

Firebase-root
   |
   --- users
         |
         --- uid
              |
              --- name: "John"
              |
              --- email: "john@email.com"

要打印姓名和電子郵件，請使用以下代碼和模型類：

String uid = FirebaseAuth.getInstance().getCurrentUser().getUid();

DatabaseReference rootRef = FirebaseDatabase.getInstance().getReference();
DatabaseReference uidRef = rootRef.child("users").child(uid);
ValueEventListener valueEventListener = new ValueEventListener() {
    @Override
    public void onDataChange(DataSnapshot dataSnapshot) {
        User user = dataSnapshot.getValue(User.class);
        String name = user.getUserName();
        tName.setText(name);
        String email = user.getUserEmail();
        tEmail.setText(email);
        Log.d("TAG", name + " / " + email);
    }

    @Override
    public void onCancelled(DatabaseError databaseError) {}
};
uidRef.addListenerForSingleValueEvent(valueEventListener);

如果要使用String類將它們打印得更簡單，請使用以下代碼：

String uid = FirebaseAuth.getInstance().getCurrentUser().getUid();

DatabaseReference rootRef = FirebaseDatabase.getInstance().getReference();
DatabaseReference usersRef = rootRef.child("users").child(uid);
ValueEventListener valueEventListener = new ValueEventListener() {
    @Override
    public void onDataChange(DataSnapshot dataSnapshot) {
        String name = dataSnapshot.child("name").getValue(String.class);
        tName.setText(name);
        String email = dataSnapshot.child("email").getValue(String.class);
        tEmail.setText(email);
        Log.d("TAG", name + " / " + email);
    }

    @Override
    public void onCancelled(DatabaseError databaseError) {}
};
uidRef.addListenerForSingleValueEvent(valueEventListener);

在這兩種情況下，輸出均為： John / john@email.com